如何基于单选按钮显示gridview

我在高级搜索表单中使用了两个单选按钮，它们是已审核和未审核的。当我点击Revied时，它应该在Gridview中过滤多个搜索框并显示结果。还有另外三个字段“更新日期”、“审核日期”和“创建日期”。假设我点击Review按钮。它应该检查条件更新时间是否大于创建日期，检查日期是否为默认值（0000-00-00 00:00:00），并在gridview中显示结果

SQL query-Select * from test where (updateddate>createddate)and(revieweddate=='0000-00-00 00:00:00');  

类似地，当我单击NotReview时，它应该检查UpdateDate=createddate和revieweddate=NULL

   SQL query-Select * from test where (updateddate=createddate)and(revieweddate IS NULL);   

下面是我尝试过的代码，但没有得到正确的结果。如何执行正确的结果

    $criteria->compare('ReviewedDate',$this->ReviewedDate,true);
             if($this->ReviewedDate != '') {
    $criteria->addCondition(
        'ReviewedDate ' . ($this->ReviewedDate=='1' ? 'IS NOT NULL' : 'IS NULL'));

}
else {
    $criteria->addCondition('ReviewedDate IS NULL');
}

---

您可以在网格视图中使用客户过滤器（如下拉列表），获取该字段的值并在其中实现您的逻辑，如：

在你看来：

$this->widget('zii.grid.GridView' , array(
'id' => 'urGrid',
'dataProvider' => $model->search,
'columns' => array(
        array(
           'name' => 'ReviewedDate',
           'filter' => CHtml::dropDownList('customeField' , $_GET['customeField'] , array(0=>'not reviewed' , 1=>'reviewed' , 2=>'some other thing'))
        ),
         .
         .
         .
    ),
));

在saerch函数中，捕获此自定义字段值：

public function search() {
    $criteria = new CDbCriteria;

    //$criteria->compare('col1', $this->col1);
    $criteria->compare('col2', $this->col2);
    .
    .
    .
    if(isset($_GET['customeField'])){  // implement your logic in here
        if($_GET['customeField'] == 1){
              $criteria->addCondition('t.updateddate > t.createddate);  //add your logic
              $criteria->compare('revieweddate' ,'0000-00-00 00:00:00'); //check for exact thing
         }
         else{ anothe thing ..}
    }

干杯