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Haskell倍数，如果不是

haskell

Haskell倍数，如果不是,haskell,Haskell,您好，我正在尝试使用叠瓦条件，但我发现解析错误： parse error on input ‘|’ isAssignMent::String->Bool isAssignMent a | a == "" = False | otherwise | (head trimmed) == '=' = True | otherwise = False where trimmed = trimRightSid

您好，我正在尝试使用叠瓦条件，但我发现解析错误：

parse error on input ‘|’

isAssignMent::String->Bool
isAssignMent a
    | a == "" = False
    | otherwise
        | (head trimmed) == '=' = True
        | otherwise = False
        where 
            trimmed = trimRightSide a [' ', '\n']
我做错了什么？谢谢你这是你想要的吗

isAssignMent::String->Bool
isAssignMent a
    | a == "" = False
    | (head trimmed) == '=' = True
    | otherwise = False
        where 
            trimmed = trimRightSide a [' ', '\n']
按顺序检查保护子句。你只需要在末尾加一个
否则
子句。

这就是你想要的吗

isAssignMent::String->Bool
isAssignMent a
    | a == "" = False
    | (head trimmed) == '=' = True
    | otherwise = False
        where 
            trimmed = trimRightSide a [' ', '\n']
按顺序检查保护子句。您只需要在结尾处添加一个
或
子句。
您还可以使用模式匹配更习惯地编写此语句：


isAssignMent::String->Bool
isAssignMent ""         = False
isAssignMent a
    | '=':_ <- trimmed  = True
    | otherwise         = False
    where 
        trimmed = trimRightSide a [' ', '\n']



isAssignMent:：String->Bool
isAssignMent“”=错误
分配a

|“=”：您还可以使用模式匹配更习惯地编写：


isAssignMent::String->Bool
isAssignMent ""         = False
isAssignMent a
    | '=':_ <- trimmed  = True
    | otherwise         = False
    where 
        trimmed = trimRightSide a [' ', '\n']



isAssignMent:：String->Bool
isAssignMent“”=错误
分配a

|“=”：(
否则
只是
真的同义词
否则
只是
真的同义词