Hibernate HQL返回关联联接，如何在条件中执行此操作？

我正在使用HQL进行动态查询，但由于有许多参数，我相信这些条件会更“可读”。查询如下所示：

String queryString = "select u from ReportSalesUnit as r join r.recipients as u where r.id = :reportSalesUnitId";
if ( firstName != null )
{
    queryString += " and lower(u.firstName) like :firstName";
}
if ( lastName != null )
{
    queryString += " and lower(u.lastName) like :lastName";
}
if ( email != null )
{
    queryString += " and lower(u.email) like :email";
}
if ( phoneNr != null )
{
    queryString += " and u.phoneNr like :phoneNr";
}
Query query = session.createQuery( queryString );
if ( firstName != null )
{
    query.setParameter( "firstName", firstName.toLowerCase() + "%" );
}
if ( lastName != null )
{
    query.setParameter( "lastName", lastName.toLowerCase() + "%" );
}
if ( email != null )
{
    query.setParameter( "email", email.toLowerCase() + "%" );
}
if ( phoneNr != null )
{
    query.setParameter( "phoneNr", phoneNr + "%" );
}
query.setParameter( "reportSalesUnitId", reportSalesUnitId );

...
if(firstName != null) {   
   criteria.add(Restrictions.and(
      Restrictions.isNotNull("firstName"), Restrictions.eq("firstName", firstName.toLowerCase());
...

criteria.createAlias("recipients", "recipients", JoinType.LEFT_OUTER_JOIN);

---

老实说，我不知道如何返回与条件关联的join。我在这里寻找答案，但找不到答案：，有人能帮我吗？稍微解释一下就好了。

标准也可以这样使用：

String queryString = "select u from ReportSalesUnit as r join r.recipients as u where r.id = :reportSalesUnitId";
if ( firstName != null )
{
    queryString += " and lower(u.firstName) like :firstName";
}
if ( lastName != null )
{
    queryString += " and lower(u.lastName) like :lastName";
}
if ( email != null )
{
    queryString += " and lower(u.email) like :email";
}
if ( phoneNr != null )
{
    queryString += " and u.phoneNr like :phoneNr";
}
Query query = session.createQuery( queryString );
if ( firstName != null )
{
    query.setParameter( "firstName", firstName.toLowerCase() + "%" );
}
if ( lastName != null )
{
    query.setParameter( "lastName", lastName.toLowerCase() + "%" );
}
if ( email != null )
{
    query.setParameter( "email", email.toLowerCase() + "%" );
}
if ( phoneNr != null )
{
    query.setParameter( "phoneNr", phoneNr + "%" );
}
query.setParameter( "reportSalesUnitId", reportSalesUnitId );

...
if(firstName != null) {   
   criteria.add(Restrictions.and(
      Restrictions.isNotNull("firstName"), Restrictions.eq("firstName", firstName.toLowerCase());
...

criteria.createAlias("recipients", "recipients", JoinType.LEFT_OUTER_JOIN);

看起来，它不会有更多的可读性与许多条件。但是

标准

可以在以下方面帮助您：

在达到

标准

/

查询

创建之前，应预先检查空值（或其他例外）。最后，您将获得如下代码，我想这对您来说是可以接受的：

... 
criteria.add(Restrictions.eq("firstName", firstName.toLowerCase()));
criteria.add(Restrictions.eq("phoneNr", phoneNr));
...
criteria.list();

并且，您可以通过以下别名创建联接或获取数据：

String queryString = "select u from ReportSalesUnit as r join r.recipients as u where r.id = :reportSalesUnitId";
if ( firstName != null )
{
    queryString += " and lower(u.firstName) like :firstName";
}
if ( lastName != null )
{
    queryString += " and lower(u.lastName) like :lastName";
}
if ( email != null )
{
    queryString += " and lower(u.email) like :email";
}
if ( phoneNr != null )
{
    queryString += " and u.phoneNr like :phoneNr";
}
Query query = session.createQuery( queryString );
if ( firstName != null )
{
    query.setParameter( "firstName", firstName.toLowerCase() + "%" );
}
if ( lastName != null )
{
    query.setParameter( "lastName", lastName.toLowerCase() + "%" );
}
if ( email != null )
{
    query.setParameter( "email", email.toLowerCase() + "%" );
}
if ( phoneNr != null )
{
    query.setParameter( "phoneNr", phoneNr + "%" );
}
query.setParameter( "reportSalesUnitId", reportSalesUnitId );

...
if(firstName != null) {   
   criteria.add(Restrictions.and(
      Restrictions.isNotNull("firstName"), Restrictions.eq("firstName", firstName.toLowerCase());
...

criteria.createAlias("recipients", "recipients", JoinType.LEFT_OUTER_JOIN);

或

---

事实上这不是我想要的。我的选择看起来是这样的：

从ReportSalesUnit中选择u作为r join r.recipients作为u

，我想知道如何使用条件返回关联的join（

r.recipients

），而不是从ReportSalesUnit中选择

作为r

来创建HQL，比如说我创建了这样的条件：

criteria.createCriteria>（ReportSalesUnit.class）

，要返回我提到的asso~join，我只需要添加

条件.createAlias（“recipients”，“recipients”）；.setFetchMode（“recipients”，FetchMode.join）；

和简单的

条件.list（）

？或其他方法