Hibernate 使用HSQL内存数据库作为JPA数据源
我有一个内存中的数据源:Hibernate 使用HSQL内存数据库作为JPA数据源,hibernate,jpa,persistence,jpa-2.0,hsqldb,Hibernate,Jpa,Persistence,Jpa 2.0,Hsqldb,我有一个内存中的数据源: java.sql.Connection c = DriverManager.getConnection("jdbc:hsqldb:mem:testdb", "sa", ""); emf = Persistence.createEntityManagerFactory("manager"); 但现在我被卡住了。我想将其用作J2SE应用程序中的JPA数据源。我浏览了整个网站,但所有信息都与J2EE相关 <persistence xmlns="
java.sql.Connection c = DriverManager.getConnection("jdbc:hsqldb:mem:testdb", "sa", "");
emf = Persistence.createEntityManagerFactory("manager");
但现在我被卡住了。我想将其用作J2SE应用程序中的JPA数据源。我浏览了整个网站,但所有信息都与J2EE相关
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"
version="2.0">
<persistence-unit name="manager">
<jta-data-source>/*What to enter here?*/</jta-data-source>
<properties>
<property name="hibernate.dialect" value="org.hibernate.dialect.HSQLDialect" />
<property name="hibernate.hbm2ddl.auto" value="create-drop" />
</properties>
</persistence-unit>
</persistence>
/*在这里输入什么*/
/*在这里输入什么*/
没什么。在Java SE环境中,您必须使用JPA提供商提供的内置连接池,设置如下所示:
<persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd" version="2.0">
<persistence-unit name="manager" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<class>com.acme.Foo</class>
...
<properties>
<property name="javax.persistence.jdbc.driver" value="org.hsqldb.jdbcDriver"/>
<property name="javax.persistence.jdbc.url" value="jdbc:hsqldb:mem:testdb"/>
<property name="javax.persistence.jdbc.user" value="sa"/>
<property name="javax.persistence.jdbc.password" value=""/>
<property name="hibernate.dialect" value="org.hibernate.dialect.HSQLDialect"/>
<property name="hibernate.hbm2ddl.auto" value="update"/>
</properties>
</persistence-unit>
</persistence>
org.hibernate.ejb.HibernatePersistence
com.acme.Foo
...
谢谢,它很有效。我现在有另一个问题: