Hibernate '中的未知列；其中第'条；将detachedcriteria与collections属性一起使用时

我有3个表：BookInfo、AuthorInfo和BookAuthors

BookInfo与BookAuthors有一对多关系。 BookInfo.hbm.xml中的映射：

<set name="bookAuthorsesByBookId" inverse="true">
    <key>
        <column name="book_id" not-null="true"/>
    </key>
    <one-to-many not-found="ignore" class="com.pojo.hibernate.BookAuthors"/>
</set>

<set name="bookAuthorsesByAuthorId" inverse="true">
    <key>
        <column name="author_id" not-null="true"/>
    </key>
    <one-to-many not-found="ignore" class="com.pojo.hibernate.BookAuthors"/>
</set>

但是，它会产生一个错误。 汇总错误：

org.springframework.dao.InvalidDataAccessResourceUsageException: could not execute query; SQL [select this_.book_id as book1_7_2_,....]; nested exception is org.hibernate.exception.SQLGrammarException: could not execute query
Caused by: org.hibernate.exception.SQLGrammarException: could not execute query
Caused by: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Unknown column 'authorinfo2_.author_name' in 'where clause'

它生成的查询是：

select this_.book_id as book1_7_2_, ... from book.book_info this_ 
inner join book.book_authors authors1_ on this_.book_id=authors1_.book_id
where (author2_.author_name like ?)

完整查询：

SELECT this_.book_id              AS book1_7_2_,
   this_.isbn_10              AS isbn2_7_2_,
   this_.isbn_13              AS isbn3_7_2_,
   this_.book_title           AS book4_7_2_,
   this_.book_subtitle        AS book5_7_2_,
   this_.book_description     AS book6_7_2_,
   this_.no_of_pages          AS no7_7_2_,
   this_.book_mrp             AS book8_7_2_,
   this_.book_language        AS book9_7_2_,
   this_.book_format          AS book10_7_2_,
   this_.book_img_url         AS book11_7_2_,
   this_.publishing_date      AS publishing12_7_2_,
   this_.verified             AS verified7_2_,
   this_.publisher_id         AS publisher14_7_2_,
   publisher3_.publisher_id   AS publisher1_19_0_,
   publisher3_.publisher_name AS publisher2_19_0_,
   bookauthor1_.book_id       AS book1_5_1_,
   bookauthor1_.author_id     AS author2_5_1_
FROM   book.book_info this_
   INNER JOIN book.publisher_info publisher3_
           ON this_.publisher_id = publisher3_.publisher_id
   INNER JOIN book.book_authors bookauthor1_
           ON this_.book_id = bookauthor1_.book_id
WHERE  ( ( this_.book_title LIKE ?
        OR authorinfo2_.author_name LIKE ?
        OR publisher3_.publisher_name LIKE ?
        OR this_.isbn_10 LIKE ?
        OR this_.isbn_13 LIKE ? )
     AND 1 = 1 ) 

---

这不是你要找的问题。未知列“authorInfo.author\u name”表示查询在

where

子句中具有该值。基本上，您提供的sql与您的错误不匹配。只要找到hibernate抱怨的查询，您就会发现字段

author\u name

在不正确的表中被搜索。查询是相同的。我仍然添加了完整的查询。我不知道为什么它使用authorinfo2_uu2;alias，尽管它没有生成该别名。那么，如果直接在sql工具中执行查询（添加参数值），查询是否有效？Hibernate日志发布从数据库检索的内容。如果将该查询日志放入SQL工具中，它们也应该可以工作。只要试着在日志中找到不起作用的字段，看看查询中有什么失败。当我添加：

internal JOIN book.author\u info authorinfo2\uon bookauthor1.author\u id=authorinfo2.author\u id

时，它就起作用了。但是，我不知道如何使用分离的条件添加它。这就是

createAlias

所做的，基本上，它执行一个连接操作。你基本上拥有的是一个多对多的关系，但在我看来，你把它映射为一个不必要的一对多关系。映射双向多对多关系，让书与作者以及作者与书直接在实体中，不是更容易吗？只是设计一件事。

select this_.book_id as book1_7_2_, ... from book.book_info this_ 
inner join book.book_authors authors1_ on this_.book_id=authors1_.book_id
where (author2_.author_name like ?)

SELECT this_.book_id              AS book1_7_2_,
   this_.isbn_10              AS isbn2_7_2_,
   this_.isbn_13              AS isbn3_7_2_,
   this_.book_title           AS book4_7_2_,
   this_.book_subtitle        AS book5_7_2_,
   this_.book_description     AS book6_7_2_,
   this_.no_of_pages          AS no7_7_2_,
   this_.book_mrp             AS book8_7_2_,
   this_.book_language        AS book9_7_2_,
   this_.book_format          AS book10_7_2_,
   this_.book_img_url         AS book11_7_2_,
   this_.publishing_date      AS publishing12_7_2_,
   this_.verified             AS verified7_2_,
   this_.publisher_id         AS publisher14_7_2_,
   publisher3_.publisher_id   AS publisher1_19_0_,
   publisher3_.publisher_name AS publisher2_19_0_,
   bookauthor1_.book_id       AS book1_5_1_,
   bookauthor1_.author_id     AS author2_5_1_
FROM   book.book_info this_
   INNER JOIN book.publisher_info publisher3_
           ON this_.publisher_id = publisher3_.publisher_id
   INNER JOIN book.book_authors bookauthor1_
           ON this_.book_id = bookauthor1_.book_id
WHERE  ( ( this_.book_title LIKE ?
        OR authorinfo2_.author_name LIKE ?
        OR publisher3_.publisher_name LIKE ?
        OR this_.isbn_10 LIKE ?
        OR this_.isbn_13 LIKE ? )
     AND 1 = 1 )