如何在Hibernate中选择数组大小为0的对象？

我正在使用Hibernate，我有如下功能：

public class Product{
  private Integer id;
  private List<Price> prices;

  // getters and setters
}

public class Price{
  private Integer id;
  private Double price;
  private Product product;
  private List<Recipe> recipes;

  // getters and setters
}

public class Recipe{
  private Integer q;

  //getters and setters
}

List<Product> products = session.createQuery(
    "select product from Price p"
    + " inner join p.recipes where p.recipes = null ").list();

我想知道我是否可以做以下事情：

public class Product{
  private Integer id;
  private List<Price> prices;

  // getters and setters
}

public class Price{
  private Integer id;
  private Double price;
  private Product product;
  private List<Recipe> recipes;

  // getters and setters
}

public class Recipe{
  private Integer q;

  //getters and setters
}

List<Product> products = session.createQuery(
    "select product from Price p"
    + " inner join p.recipes where p.recipes = null ").list();

---

我想从没有任何配方的prices中选择所有产品

您好，我尝试了您的解决方案，但我不推荐使用LEFT_JOIN，因此我将其替换为JoinType.LEFT_OUTER_JOIN，但我仍然获得所有产品。这个限制不起作用。session.createCriteriaProduct.class.createAliasprices，prices.createAliasprices，recipes，recipes，recipes，JoinType.LEFT_OUTER_JOIN.addRestrictions.isNullrecipes.id.setResultTransformerCriteriaSpecification.DISTINCT_ROOT_ENTITY.list；

session.createCriteria(Product.class).createAlias("prices", "prices")
            .createAlias("prices.recipes", "recipes", Criteria.LEFT_JOIN)
            .add(Restrictions.isNull("recipes.id"))
            .setResultTransformer(CriteriaSpecification.DISTINCT_ROOT_ENTITY).list();