Hibernate 休眠@manytone和@OneToMany以列表形式获取数据（记录数）_Hibernate_Spring Mvc_Hibernate Mapping_Entity Relationship_Hbmxml

Hibernate 休眠@manytone和@OneToMany以列表形式获取数据（记录数）

hibernate spring-mvc

Hibernate 休眠@manytone和@OneToMany以列表形式获取数据（记录数）,hibernate,spring-mvc,hibernate-mapping,entity-relationship,hbmxml,Hibernate,Spring Mvc,Hibernate Mapping,Entity Relationship,Hbmxml,我有两张桌子 1.Org[Org\u ID，PARENT\u ID，LANG\u ID（参考LANG）] 2.语言[语言ID，语言名称] 我的JAVA实体文件 Lang.java @Entity @JsonIdentityInfo(generator = ObjectIdGenerators.PropertyGenerator.class, property = "langId") @JsonIgnoreProperties({ "hibernateLazyInitializer", "hand

我有两张桌子
1.Org[Org\u ID，PARENT\u ID，LANG\u ID（参考LANG）] 2.语言[语言ID，语言名称]

我的JAVA实体文件

Lang.java

@Entity
@JsonIdentityInfo(generator = ObjectIdGenerators.PropertyGenerator.class, property = "langId")
@JsonIgnoreProperties({ "hibernateLazyInitializer", "handler" })
@SuppressWarnings("serial")
public class Lang implements java.io.Serializable {
    private BigDecimal langId;
    private String langName;
    private Set<Org> orgs = new HashSet<Org>(0);
    public Lang() {
    }
    public Lang(BigDecimal langId, Set<Org> orgs) {
        this.langId = langId;
        this.orgs = orgs;
    }
    public BigDecimal getLangId() {
        return this.langId;
    }
    public void setLangId(BigDecimal langId) {
        this.langId = langId;
    }
    public String getLangName() {
        return this.langName;
    }
    public void setLangName(String langName) {
        this.langName = langName;
    }public void setOrgs(Set<Org> orgs) {
        this.orgs = orgs;
    }
}

    @Entity
@JsonIdentityInfo(generator = ObjectIdGenerators.PropertyGenerator.class, property = "orgId")
@JsonIgnoreProperties({ "hibernateLazyInitializer", "handler" })
@SuppressWarnings("serial")
public class Org implements java.io.Serializable {
    @Id
    @Column(name = "orgId")
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private BigDecimal orgId;   
    private BigDecimal parentOrgId;
    @JsonIdentityInfo(generator = ObjectIdGenerators.PropertyGenerator.class, property = "langId",scope=Lang.class)
    public Org() {
    }
    public Org(BigDecimal orgId, BigDecimal parentOrgId, Lang lang) {
        this.orgId = orgId;
        this.parentOrgId = parentOrgId;
        this.lang = lang;
    }
    public BigDecimal getOrgId() {
        return this.orgId;
    }
    public void setOrgId(BigDecimal orgId) {
        this.orgId = orgId;
    }
    public BigDecimal getParentOrgId() {
        return this.parentOrgId;
    }
    public void setParentOrgId(BigDecimal parentOrgId) {
        this.parentOrgId = parentOrgId;
    }
    @ManyToOne(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
    public Lang getLang() {
        return this.lang;
    }
    public void setLang(Lang lang) {
        this.lang = lang;
    }
}

我的HBM Xml文件

Org.hbm.xml

    <hibernate-mapping package="com.test.entity">
    <class name="com.test.entity.Org" table="ORG">
    <id name="orgId" type="big_decimal">
        <column name="ORG_ID" precision="22" scale="0" />
        <generator class="increment" />
    </id>        
    <property name="parentOrgId" type="big_decimal">
        <column name="PARENT_ORG_ID" precision="22" scale="0" not-null="true" />
    </property>
    <many-to-one name="lang" class="com.test.entity.Lang" fetch="select">
        <column name="LANG_ID" precision="22" scale="0" not-null="true" />
    </many-to-one>        
    </class>
</hibernate-mapping>

    <hibernate-mapping package="com.test.entity">
    <class name="com.test.entity.Lang" table="LANG">
    <id name="langId" type="big_decimal">
        <column name="LANG_ID" precision="22" scale="0" />
        <generator class="increment" />
    </id>
    <property name="langName" type="string">
        <column name="LANG_NAME" length="32" not-null="true" unique="true" />
    </property>
    <set name="orgs" table="ORG" inverse="true" lazy="true" fetch="select">
        <key>
        <column name="LANG_ID" precision="22" scale="0" not-null="true" />
        </key>
        <one-to-many class="com.test.entity.Org" />
    </set>
    </class>
</hibernate-mapping>

此处货币也与郎相同，将其货币Id引用到货币

我无法获取数组中的第二和第三个组织数据，它有Lang.Orgs和Lang.Orgs.Currency两种版本

请帮忙，谢谢

这将让您开始，我正在使用Spring JPA2和Hibernate以及Jackson

我让Hibernate从实体创建表

Spring应用程序上下文如下所示：

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:jdbc="http://www.springframework.org/schema/jdbc"
    xmlns:jpa="http://www.springframework.org/schema/data/jpa" xmlns:tx="http://www.springframework.org/schema/tx"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:cache="http://www.springframework.org/schema/cache"
    xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
    http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd
    http://www.springframework.org/schema/jdbc http://www.springframework.org/schema/jdbc/spring-jdbc.xsd
    http://www.springframework.org/schema/data/jpa http://www.springframework.org/schema/data/jpa/spring-jpa.xsd
    http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd
    http://www.springframework.org/schema/cache http://www.springframework.org/schema/cache/spring-cache.xsd">

    <context:component-scan base-package="com.greg" />
    <tx:annotation-driven />
    <jpa:repositories base-package="com.greg.repository" />

    <bean id="dataSource"
        class="org.springframework.jdbc.datasource.DriverManagerDataSource">
        <property name="driverClassName" value="org.h2.Driver" />
        <property name="url" value="jdbc:h2:mem:test;DB_CLOSE_DELAY=-1" />
        <property name="username" value="sa" />
        <property name="password" value="" />
    </bean>

    <bean id="entityManagerFactory"
        class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
        <property name="dataSource" ref="dataSource" />
        <property name="packagesToScan" value="com.greg.entity" />
        <property name="jpaVendorAdapter">
            <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter" />
        </property>
        <property name="jpaProperties">
            <props>
                <prop key="hibernate.hbm2ddl.auto">create</prop>
                <prop key="hibernate.show_sql">false</prop>
                <prop key="hibernate.format_sql">false</prop>
                <prop key="hibernate.dialect">org.hibernate.dialect.H2Dialect</prop>
            </props>
        </property>
    </bean>

    <bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
        <property name="entityManagerFactory" ref="entityManagerFactory" />
    </bean>

</beans>

这将创建问题中的表格

Spring JPA存储库很简单：

@Repository
@Transactional
public interface OrgRepository extends CrudRepository<Org, Long> {
}

我的测试是：

    @Test
@Transactional
public void test1() {

    try {
        Lang lang = makeLang("EN");
        langRepository.save(lang);
        assertNotNull(lang.getLangId());

        Org org1 = new Org();
        org1.setLang(lang);
        orgRepository.save(org1);

        Org org2 = new Org();
        org2.setLang(lang);
        org2.setParent(org1);
        orgRepository.save(org2);

        Org org3 = new Org();
        org3.setLang(lang);
        org3.setParent(org2);
        orgRepository.save(org3);

        assertEquals("EN", orgRepository.findOne(org1.getOrgId()).getLang().getLangName());
        assertNull(orgRepository.findOne(org1.getOrgId()).getParent());

        assertEquals("EN", orgRepository.findOne(org2.getOrgId()).getLang().getLangName());
        assertEquals(org1.getOrgId().longValue(), orgRepository.findOne(org2.getOrgId()).getParent().getOrgId().longValue());

        assertEquals("EN", orgRepository.findOne(org3.getOrgId()).getLang().getLangName());
        assertEquals(org2.getOrgId().longValue(), orgRepository.findOne(org3.getOrgId()).getParent().getOrgId().longValue());

        System.out.println(new ObjectMapper().writeValueAsString(org3));

        showTables("ORG");
        showTables("LANG");
    } catch (Exception e) {
        e.printStackTrace();
        fail();
    }
}

private Lang makeLang(String name) {
    Lang lang = new Lang();
    lang.setLangName(name);
    return lang;
}

请提供控制器方法的代码

getAllChildWithParetOrgs（parentId）。那会更有帮助。另外，根据我对hibernate查询连接和数据库快照的理解，我认为JSON输出不应该再登记记录。请查看以下解释：
因为您传递的parentId为0。根据hibernate查询联接和数据库快照，似乎没有OrgId=0的单独记录。
从子句的parentOrgId=0部分，它指的是子项：orgId为1的记录。
随后，它指的是orgId=1的子记录，即parentOrgId=1的记录，即orgId=2和orgId=3的记录。我不认为你的JSON对象应该在那之后获得更多的结果
@Entity
public class Org {

    @Id
    @Column(name = "org_id")
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Long orgId;

    @ManyToOne(fetch = FetchType.EAGER)
    @JoinColumn(name = "lang_id", referencedColumnName = "lang_id", updatable = false, insertable = false, nullable = false)
    private Lang lang;

    @ManyToOne(fetch = FetchType.EAGER)
    @JoinColumn(name = "parent_id", referencedColumnName = "org_id", updatable = false, insertable = false, nullable = false)
    private Org parent;

@Repository
@Transactional
public interface OrgRepository extends CrudRepository<Org, Long> {
}

@Repository
@Transactional
public interface OrgRepository extends CrudRepository<Lang, Long> {
}

    {
    "orgId": 4,
    "lang": {
        "langId": 1,
        "langName": "EN",
        "orgs": null
    },
    "parent": {
        "orgId": 3,
        "lang": {
            "langId": 1,
            "langName": "EN",
            "orgs": null
        },
        "parent": {
            "orgId": 2,
            "lang": {
                "langId": 1,
                "langName": "EN",
                "orgs": null
            },
            "parent": null
        }
    }
}

    @Test
@Transactional
public void test1() {

    try {
        Lang lang = makeLang("EN");
        langRepository.save(lang);
        assertNotNull(lang.getLangId());

        Org org1 = new Org();
        org1.setLang(lang);
        orgRepository.save(org1);

        Org org2 = new Org();
        org2.setLang(lang);
        org2.setParent(org1);
        orgRepository.save(org2);

        Org org3 = new Org();
        org3.setLang(lang);
        org3.setParent(org2);
        orgRepository.save(org3);

        assertEquals("EN", orgRepository.findOne(org1.getOrgId()).getLang().getLangName());
        assertNull(orgRepository.findOne(org1.getOrgId()).getParent());

        assertEquals("EN", orgRepository.findOne(org2.getOrgId()).getLang().getLangName());
        assertEquals(org1.getOrgId().longValue(), orgRepository.findOne(org2.getOrgId()).getParent().getOrgId().longValue());

        assertEquals("EN", orgRepository.findOne(org3.getOrgId()).getLang().getLangName());
        assertEquals(org2.getOrgId().longValue(), orgRepository.findOne(org3.getOrgId()).getParent().getOrgId().longValue());

        System.out.println(new ObjectMapper().writeValueAsString(org3));

        showTables("ORG");
        showTables("LANG");
    } catch (Exception e) {
        e.printStackTrace();
        fail();
    }
}

private Lang makeLang(String name) {
    Lang lang = new Lang();
    lang.setLangName(name);
    return lang;
}