Hibernate Struts2休眠一对多关系1323
我试图使用struts2和hibernate一对多关系显示两个表活动和收藏夹中的值Hibernate Struts2休眠一对多关系1323,hibernate,struts2,Hibernate,Struts2,我试图使用struts2和hibernate一对多关系显示两个表活动和收藏夹中的值 //Activities @Entity @Table(name="ACTIVITIES") @OneToMany(fetch = FetchType.EAGER, mappedBy = "activities" , targetEntity=Favorites.class, cascade=CascadeType.ALL ) pu
//Activities
@Entity
@Table(name="ACTIVITIES")
@OneToMany(fetch = FetchType.EAGER, mappedBy = "activities" , targetEntity=Favorites.class, cascade=CascadeType.ALL )
public Set<Favorites> getFavorites() {
return favorites;
}
public void setFavorites(Set<Favorites> favorites) {
this.favorites = favorites;
}
@Id
@GeneratedValue
@Column(name="ACTIVITYID")
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
//Favorites
@Entity
@Table(name="Favorites")
@ManyToOne(optional=false)
public Activities getActivities() {
return this.activities;
}
在jsp中,我尝试了下面这样的方法,在这种情况下,来自数据库本身的值不是comming
<s:iterator value="%{favorites}" id="fav" status="myStat">
<s:checkbox id="accFavorities" value="activityList[%{#activityStatus.index}].fav[%{#myStat.index}].accFavorities"/></td>
非常感谢您的帮助
谢谢您必须定义您的复选框,以便当浏览器提交表单时,参数名称与预期的bean结构匹配
也许您可以尝试的键属性,如所示,谢谢,但我对一个常见的嵌套迭代器有点问题,我参考了
for (Activities al : activityList) {
for (Favorites ss : al.getFavorites()) {
System.out.println(ss.getCompany());
System.out.println(ss.getAccFavorities());
}
}
<s:iterator value="%{favorites}" id="fav" status="myStat">
<s:checkbox id="accFavorities" value="activityList[%{#activityStatus.index}].fav[%{#myStat.index}].accFavorities"/></td>