Hive 配置单元拆分函数获取元素数

我想知道Hive是否有从字符串中获取元素数量的选项，例如

david.Udert

。我尝试了这个

拆分（键入“\\”）[2][3]

这个

拆分（键入“\\”）[2:3]

不起作用， 有没有办法这样做来把这两个词组合在一起

• 数组索引以

  0开始
  
  with t as (select 'Now.I.heard.you.know.that.secret.chord' as mycol)
  
  select  split(t.mycol,'\\.')    as arr
     ,split(t.mycol,'\\.')[0] as arr_1st_element
     ,split(t.mycol,'\\.')[1] as arr_2nd_element
     ,split(t.mycol,'\\.')[2] as arr_3nd_element
  
  from    t
  ;
  
  
  

• 至少目前不支持阵列切片。如果要切片，请在分割之前进行

  with t as (select 'Now.I.heard.you.know.that.secret.chord' as mycol)
  
  select  split(substring_index(substring_index(t.mycol,'.',7),'.',-3),'\\.')     as slice_option_1
     ,split(regexp_extract(t.mycol,'(.*?\\.){4}((\\.?[^.]*){0,3})',2),'\\.')  as slice_option_2
  
  from    t
  ;
  

  ---

---

“它不起作用”不是一个合理的描述。你有错误吗？问题被卡住了吗？hive-server2服务崩溃了吗？你的电脑着火了吗？你实际想要的结果是什么？

with t as (select 'Now.I.heard.you.know.that.secret.chord' as mycol)

select  split(substring_index(substring_index(t.mycol,'.',7),'.',-3),'\\.')     as slice_option_1
   ,split(regexp_extract(t.mycol,'(.*?\\.){4}((\\.?[^.]*){0,3})',2),'\\.')  as slice_option_2

from    t
;

+--------------------------+--------------------------+
|      slice_option_1      |      slice_option_2      |
+--------------------------+--------------------------+
| ["know","that","secret"] | ["know","that","secret"] |
+--------------------------+--------------------------+