Hive 蜂巢多选

结果：

CID    F_ID       NME
1       A          QR
1       B          QB
2       A          QR
3       B          QB
4       A          QR
4       B          QB

在配置单元中，用于获取结果的查询应该只输出CID

---

在F_ID-A和B中，我可以使用oracle中的LISTAGG实现相同的结果

此查询将在单个map reduce阶段执行：

CID F_ID    NME
1    A      QR
1    B      QB
4    A      QR
4    B      QB

演示：

结果:

select CID,    F_ID,       NME  from
(
select s.*, 
       sum(A) over (partition by CID) A_cnt,
       sum(B) over (partition by CID) B_cnt
from
(
select s.*,
       case when F_ID='A' then 1 else 0 end A,
       case when F_ID='B' then 1 else 0 end B
 from
( --replace this subquery (s) with your table  
  select stack(6,
  1,       'A',          'QR',
  1,       'B',          'QB',
  2,       'A',          'QR',
  3,       'B',          'QB',
  4,       'A',          'QR',
  4,       'B',          'QB') as (CID,    F_ID,       NME)
) s
)s
)s where A_cnt>=1 and B_cnt >=1
;

---

感谢leftjoin的响应，它非常有用，如果在中执行相同的查询，您能告诉我性能的改进吗Impala@kalis，我无法帮助您改进Impala性能，抱歉，因为我不使用Impala，在AWS平台上工作。用执行日志等问这个问题，社区的人肯定会帮你解决这个问题。

select CID,    F_ID,       NME  from
(
select s.*, 
       sum(A) over (partition by CID) A_cnt,
       sum(B) over (partition by CID) B_cnt
from
(
select s.*,
       case when F_ID='A' then 1 else 0 end A,
       case when F_ID='B' then 1 else 0 end B
 from
( --replace this subquery (s) with your table  
  select stack(6,
  1,       'A',          'QR',
  1,       'B',          'QB',
  2,       'A',          'QR',
  3,       'B',          'QB',
  4,       'A',          'QR',
  4,       'B',          'QB') as (CID,    F_ID,       NME)
) s
)s
)s where A_cnt>=1 and B_cnt >=1
;

MapReduce Jobs Launched:
Stage-Stage-1: Map: 1  Reduce: 1   Cumulative CPU: 6.39 sec   HDFS Read: 13549 HDFS Write: 28 SUCCESS
Total MapReduce CPU Time Spent: 6 seconds 390 msec
OK
1       B       QB
1       A       QR
4       B       QB
4       A       QR
Time taken: 108.779 seconds, Fetched: 4 row(s)