从mysql到html表中统计每月每天的记录

我想把所有mySql结果放在一个html表中。这是mySql：

SELECT date(vwr_date) AS mon, date(vwr_date) AS date, count(vwr_cid) AS views 
FROM car_viewer 
WHERE Year(vwr_date)='2012' AND vwr_tid='18' 
GROUP BY date 
ORDER BY date DESC

根据上面的查询，结果如下：

date        views
2012-10-23  14
2012-10-22  339
2012-10-21  305
2012-10-20  354
....
2012-10-01  291
2012-09-30  246
2012-09-29  297
...
2012-09-01  281

<table border="0" cellpadding="3" cellspacing="1" width="100%">
        <thead>
        <tr>
            <th>Mon Year / Date</th>
            <?
            for($i=1;$i<32;$i++){
                echo "<th>$i</th>";
            }
            ?>
        </tr>
    </thead>
    <tbody>
        <?
        $_thisYear=date("Y");
        $sql_nViewer="select date(vwr_date) as mon, date(vwr_date) as date, count(vwr_cid) as views from car_viewer where Year(vwr_date)='$_thisYear' and vwr_tid='$_SESSION[admin_id]' GROUP BY date ORDER BY date desc";
        echo $sql_nViewer;
        $result_nViewer=mysql_db_query($dbname,$sql_nViewer);
        $rec_nViewer=mysql_fetch_array($result_nViewer);
        $_monYear=date("M Y",strtotime($rec_nViewer[mon]));
        $_monYear2=date("Y-n",strtotime($rec_nViewer[mon]));

            echo "<tr><td>$_monYear</td>";//month name
        $day=1;
        while($rec_nViewer=mysql_fetch_assoc($result_nViewer)){
            $_nViewerDBdate=$rec_nViewer['date'];
            $_nViewerDBviews=$rec_nViewer['views'];
            echo "
            <td>$_nViewerDBviews</td>
            ";$day++;
            if($day==$_daysInMon+1){
                echo "</tr>";
            }
        }
        ?>
        </tbody>
        </table>

mysql的结果非常好。现在这是一个问题。我尝试了很多次，并根据car_viewer.vwr_date中的每个日期，以不同的方式将这些视图放入。所以我这样写：

date        views
2012-10-23  14
2012-10-22  339
2012-10-21  305
2012-10-20  354
....
2012-10-01  291
2012-09-30  246
2012-09-29  297
...
2012-09-01  281

<table border="0" cellpadding="3" cellspacing="1" width="100%">
        <thead>
        <tr>
            <th>Mon Year / Date</th>
            <?
            for($i=1;$i<32;$i++){
                echo "<th>$i</th>";
            }
            ?>
        </tr>
    </thead>
    <tbody>
        <?
        $_thisYear=date("Y");
        $sql_nViewer="select date(vwr_date) as mon, date(vwr_date) as date, count(vwr_cid) as views from car_viewer where Year(vwr_date)='$_thisYear' and vwr_tid='$_SESSION[admin_id]' GROUP BY date ORDER BY date desc";
        echo $sql_nViewer;
        $result_nViewer=mysql_db_query($dbname,$sql_nViewer);
        $rec_nViewer=mysql_fetch_array($result_nViewer);
        $_monYear=date("M Y",strtotime($rec_nViewer[mon]));
        $_monYear2=date("Y-n",strtotime($rec_nViewer[mon]));

            echo "<tr><td>$_monYear</td>";//month name
        $day=1;
        while($rec_nViewer=mysql_fetch_assoc($result_nViewer)){
            $_nViewerDBdate=$rec_nViewer['date'];
            $_nViewerDBviews=$rec_nViewer['views'];
            echo "
            <td>$_nViewerDBviews</td>
            ";$day++;
            if($day==$_daysInMon+1){
                echo "</tr>";
            }
        }
        ?>
        </tbody>
        </table>

星期一/年/日

上面代码的结果很奇怪-不是我想要的。我需要这样显示数据：

---

因此，请建议我应该做什么，使它如我所期望的。关于

您可以从mysql返回该格式的数据

SELECT MONTH_v, YEAR_V
GROUP_CONCAT(IF(day_v=1, views, null)) AS '1',
GROUP_CONCAT(IF(day_v=2, views, null)) AS '2',
----
GROUP_CONCAT(IF(day_v=31, views, null)) AS '31'
FROM
(
 SELECT DAY(vwr_date) AS day_v, 
 MONTH(vwr_date) AS MONTH_v, 
 Year(vwr_date) AS YEAR_V,
 date(vwr_date) AS date_v, 
 count(vwr_cid) AS views 
 FROM car_viewer 
 WHERE Year(vwr_date)='2012' AND vwr_tid='18' 
 GROUP BY date_v 
)
GROUP BY MONTH_v, YEAR_V 
ORDER BY MONTH_v, YEAR_V DESC

---

我有一个错误：

#1064-您的SQL语法有一个错误；查看与MySQL服务器版本对应的手册，了解使用接近'GROUP_CONCAT（IF（day_v=1，views，null））作为'1'，GROUP_CONCAT（IF（day_v=2，views，n'在第2行

的正确语法，然后我认为缺少或超过逗号可能会有问题：

\1248-每个派生表都必须有自己的别名