Html表单复选框未定义的行为
我有下面的html代码:Html表单复选框未定义的行为,html,c,cgi,Html,C,Cgi,我有下面的html代码: <html> <head><title>OPTIONS</title></head> <body> <p>Choose schedule to generate:</p> <form action='cgi-bin/mp1b.cgi'> <input type=checkbox name='tfield' value=on />
<html>
<head><title>OPTIONS</title></head>
<body>
<p>Choose schedule to generate:</p>
<form action='cgi-bin/mp1b.cgi'>
<input type=checkbox name='tfield' value=on />Teacher<input type=text name=teacher value=""/><br>
<input type=checkbox name='sfield' value=on />Subject<input type=text name=subject value=""/><br>
<input type=checkbox name='rfield' value=on />Room<input type=text name=room value=""/><br>
<input type=submit value="Generate Schedule"/>
</form>
</body>
</html>
您必须发送到C CGI程序,否则我们无法帮助您。@Jori已经插入了代码。当您单击复选框时,您确定查询字符串数据的格式是这样的吗?我的意思是,如果数据以
“tfield=on&…”“
开头,它会失败,不是吗。我还想知道谁相信关于CGI的问题是离题的。字符串“tfield=on&teacher=&sfield=on&subject=&rfield=on&room=“
无法匹配sscanf
格式“teacher=%[^&]&subject=%[^&]&room=%s”
在第二个字符处(预期为'e'
,获得'f'
)sscanf
在那里停止并返回0,您没有检查返回值(顽皮!),因此您不知道它失败了。
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main(void)
{
char *data;
printf("Content-type:text/html\n\n");
printf("<html><body>");
data = getenv("QUERY_STRING");
char teacher[1024] = "";
char subject[1024] = "";
char room[1024] = "";
sscanf(data,"teacher=%[^&]&subject=%[^&]&room=%s",teacher,subject,room);
puts(teacher);
puts(subject);
puts(room);
printf("</body></html>");
return 0;
}