Ios 复杂正则表达式文本修改
嗨,我有一个复杂的正则表达式情况Ios 复杂正则表达式文本修改,ios,regex,nsstring,nsregularexpression,Ios,Regex,Nsstring,Nsregularexpression,嗨,我有一个复杂的正则表达式情况 mainString = @"Main Term (Rounded) [Square] ~a~d~j~." 我需要像你一样把这个还给你 modifiedString* = @"Main Term (Rounded) [Square] adj." 所以~之后的每个字符必须是斜体或任何属性。 修改后,我需要“adj.”的范围,以便添加属性 多谢各位 NSError *error3 = nil; NSRegularExpression *SHRegex
mainString = @"Main Term (Rounded) [Square] ~a~d~j~."
我需要像你一样把这个还给你
modifiedString* = @"Main Term (Rounded) [Square] adj."
所以~
之后的每个字符必须是斜体或任何属性。修改后,我需要
“adj.”
的范围,以便添加属性
多谢各位
NSError *error3 = nil;
NSRegularExpression *SHRegex = [NSRegularExpression regularExpressionWithPattern:@"\\~(.|)" options:0 error:&error3];
NSArray *matches3 = [SHRegex matchesInString:mainString options:0 range:NSMakeRange(0, [mainString length])];
NSUInteger *numberOfMatches = [SHRegex numberOfMatchesInString:mainString options:0 range:NSMakeRange(0, mainString.length)];
NSString *modifiedString = [SHRegex stringByReplacingMatchesInString:mainString options:0 range:NSMakeRange(0, [string length]) withTemplate:@""];
for (NSTextCheckingResult *match in matches3) {
NSRange matchRange = [match range];
NSRange firstHalfRange = [match rangeAtIndex:1];
//NSRange secondHalfRange = [match rangeAtIndex:2];
[string addAttribute:NSForegroundColorAttributeName value:[UIColor colorWithRed:0 green:0 blue:0 alpha:1] range:matchRange];
//[string addAttribute:NSForegroundColorAttributeName value:[UIColor blueColor] range:firstHalfRange];
}
您的正则表达式实现是否支持正向查找
如果是这样的话,您可以使用
(?以下代码应该执行您想要的操作。它创建一个属性字符串
其中删除了波浪线字符,并将属性添加到
我已经添加了一些评论,希望
解释它是如何工作的
NSString *mainString = @"Main Term (Rounded) [Square] ~a~d~j~.";
NSMutableAttributedString *attrString = [[NSMutableAttributedString alloc] initWithString:mainString];
NSError *error = nil;
// Pattern that matches a tilde followed by an arbitrary character:
NSString *pattern = @"(\\~)(.)";
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:pattern options:0 error:&error];
__block NSUInteger offset = 0;
[regex enumerateMatchesInString:mainString options:0 range:NSMakeRange(0, [mainString length])
usingBlock:^(NSTextCheckingResult *result, NSMatchingFlags flags, BOOL *stop) {
NSRange firstHalfRange = [result rangeAtIndex:1]; // range of the tilde
NSRange secondHalfRange = [result rangeAtIndex:2]; // range of the following character
// Adjust locations according to the string modifications:
firstHalfRange.location += offset;
secondHalfRange.location += offset;
// Set attribute for the character:
[attrString addAttribute:NSForegroundColorAttributeName value:[UIColor colorWithRed:1 green:0 blue:0 alpha:1] range:secondHalfRange];
// Remove the tilde:
[[attrString mutableString] deleteCharactersInRange:firstHalfRange];
// Update offset:
offset -= firstHalfRange.length;
}];
根据您的评论进行更新:以下代码匹配两种模式(波浪形或插入符号后跟一个字符),并使用不同的属性进行替换
NSString *mainString = @" ~a^b~c^d";
NSMutableAttributedString *attrString = [[NSMutableAttributedString alloc] initWithString:mainString];
NSError *error = nil;
NSString *pattern = @"(\\~|\\^)(.)";
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:pattern options:0 error:&error];
__block NSUInteger offset = 0;
[regex enumerateMatchesInString:mainString options:0 range:NSMakeRange(0, [mainString length])
usingBlock:^(NSTextCheckingResult *result, NSMatchingFlags flags, BOOL *stop) {
NSRange firstHalfRange = [result rangeAtIndex:1];
NSRange secondHalfRange = [result rangeAtIndex:2];
NSString *firstMatch = [mainString substringWithRange:firstHalfRange];
// Adjust locations according to the string modifications:
firstHalfRange.location += offset;
secondHalfRange.location += offset;
// Set color attribute for the character:
if ([firstMatch isEqualToString:@"~"]) {
[attrString addAttribute:NSForegroundColorAttributeName value:[UIColor colorWithRed:1 green:0 blue:0 alpha:1] range:secondHalfRange];
} else {
[attrString addAttribute:NSForegroundColorAttributeName value:[UIColor colorWithRed:0 green:1 blue:0 alpha:1] range:secondHalfRange];
}
[[attrString mutableString] deleteCharactersInRange:firstHalfRange];
// Update offset:
offset -= firstHalfRange.length;
}];
只是想澄清一下:是否要从字符串中删除所有~
字符,并返回这些字符所包围的所有字符的位置?它是否总是~a~b~c~d~
,或者可能是~abc~d~e~
——在后一种情况下,您希望返回abc d e
“特殊匹配字符”?你有~a~d~j~。
并希望adj.
是“特殊的”。这是否意味着您只需要在特殊字符之前添加一个波浪号?它可以是Main~a~d~j~。Sub~a~d~v~。
,是的,我想删除
,并返回剩余adj.
和Main
和Sub
的范围或位置。非常感谢。这就是我需要的。我的数据基本结构在每一个应该是下标的字符之前都有一个平铺。多亏了你。但我也希望^
后面的每一个字符都是上标的。添加相同的代码就可以了,但是如果同一个条目同时有两个变量,它就会崩溃为IndexOutfrange
。有什么建议吗?