iOS时间戳计算

我想知道在iOS中是否还有其他更好的时间戳计算方法，我想知道你对这种计算方法的看法，这种计算方法是否存在问题或错误

    NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
    [formatter setDateFormat:@"MM-dd-yyyy HH:mm:ss"];

    NSDate * startDate = [formatter dateFromString:dateString];
    NSTimeInterval interval = [startDate timeIntervalSinceNow];

    int totalSeconds = abs((int)interval);

    int seconds = totalSeconds % 60;
    int minutes = (totalSeconds / 60) % 60;
    int hours = totalSeconds / 3600;
    int days = totalSeconds / (60 * 60 * 24);
    int weeks = totalSeconds / (60 * 60 * 24 * 7);
    int months = totalSeconds / (60 * 60 * 24 * 7 * 4);
    int years = totalSeconds / (60 * 60 * 24 * 7 * 4 * 12);

---

非常感谢您的回复。

正是您需要的。

您应该尝试使用NSCalendar类及其方法：

- (NSDateComponents *)components:(NSUInteger)unitFlags fromDate:(NSDate *)date

例如：

NSCalendar *calendar = [NSCalendar currentCalendar];
unsigned unitFlags = NSYearCalendarUnit | NSMonthCalendarUnit |  NSDayCalendarUnit;
NSDateComponentes *components = [calendar components: unitFlags fromDate: date];

试一试

---

我认为NSDateComponents将只返回当前日期组件，而不是总天数、周数和月数。如果我错了，请纠正我。我认为NSDateComponents将只返回当前日期组件，而不是总天数、周数和月数。如果我错了，请纠正我。我认为NSDateComponents将只返回当前日期组件，而不是总天数、周数和月数。如果我错了，请纠正我。

NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:@"MM-dd-yyyy HH:mm:ss"];

NSDate * startDate = [formatter dateFromString:dateString];

NSCalendar *calender = [NSCalendar currentCalendar];

unsigned units = (NSYearCalendarUnit|NSMonthCalendarUnit|NSWeekCalendarUnit|
             NSDayCalendarUnit|NSHourCalendarUnit|NSMinuteCalendarUnit|NSSecondCalendarUnit);
NSDateComponents *dateComponents = [calender components:units
                                               fromDate:startDate];

int seconds = dateComponents.second;
int minutes = dateComponents.minute;
int hours   = dateComponents.hour;
int days    = dateComponents.day;
int weeks   = dateComponents.week;
int months  = dateComponents.month;
int years   = dateComponents.year;