Ios 设置UIPageViewController.dataSource时,是否将无法识别的选择器发送到实例?
我试图以编程方式在子视图中创建页面视图。但是,当我将UIPageViewController的数据源设置为superviewcontroller时,出现以下错误:Ios 设置UIPageViewController.dataSource时,是否将无法识别的选择器发送到实例?,ios,swift,uipageviewcontroller,Ios,Swift,Uipageviewcontroller,我试图以编程方式在子视图中创建页面视图。但是,当我将UIPageViewController的数据源设置为superviewcontroller时,出现以下错误: -[UIView scrollView]: unrecognized selector sent to instance 0x7fc223ea8300 *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[UIVie
-[UIView scrollView]: unrecognized selector sent to instance 0x7fc223ea8300
*** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[UIView scrollView]: unrecognized selector sent to instance 0x7fc223ea8300'
这是我的密码:
import UIKit
class MainVC: UIViewController, UIPageViewControllerDataSource {
private var pages: [UIViewController]
private let pageVC: UIPageViewController
init() {
pages = [UIViewController]()
for i in 0...1 {
let vc = UIViewController()
vc.view = MyUIViewSubclass(index: i)
pages.append(vc)
}
pageVC = UIPageViewController(transitionStyle: .Scroll, navigationOrientation: .Horizontal, options: nil)
pageVC.view = UIView()
pageVC.view.translatesAutoresizingMaskIntoConstraints = false
super.init(nibName: nil, bundle: nil)
pageVC.dataSource = self //Breakpoints indicate that this is when the exception occurs
view.addSubview(pageVC.view)
//...Autolayout...
}
required init?(coder aDecoder: NSCoder) {
fatalError("init(coder:) has not been implemented")
}
func pageViewController(pageViewController: UIPageViewController, viewControllerBeforeViewController viewController: UIViewController) -> UIViewController? {
return pages[0]
}
func pageViewController(pageViewController: UIPageViewController, viewControllerAfterViewController viewController: UIViewController) -> UIViewController? {
return pages[1]
}
}
提前感谢。pageVc.view有一个名为scrollview的iAction,它没有在您的视图控制器中声明,您需要从connections inspector中删除该iAction好的,因此我遇到了与您相同的问题,并且我找到了它发生的原因。 发生此错误的原因是您执行
pageVC.view=UIView()
操作的行。
UIPageViewController的视图有一个滚动视图,在该视图中,VCs之间滚动的魔力得以实现。通过将空UIView设置为它,您正在删除它,而不是使其能够工作。如果您想将某个内容更改为其视图,您应该直接执行,而不是设置另一个。是否在视图中添加了滚动视图?@S.Karthik否,
MyUIViewSubclass
上只有按钮。我相信scrollView消息与transitionStyle有关:。Scroll。我在完全相同的代码行中遇到了相同的问题,当然我使用了相同的方法(将代码分为视图、代理和控制器)。您找到了解决方案吗??