如何在ios中获取所有坐标点（X和Y）

我正在编写一个应用程序，它允许用户在视图中绘制他们想要的任何东西。当他们绘图时，我使用Json将坐标值同时发送到web，并在web中绘制相同的图表。当我慢慢画的时候，我会得到所有的坐标值，就像这样

{"XY":["92,240","94,240","96,240","97,240","98,240","99,240","100,240","102,240","103,240","104,240","104,240","105,240","106,240","107,240","108,240","108,240","110,240","110,240","112,240","112,240","114,240","115,240","116,240","117,240","118,240","120,240","120,240","120,240","122,240","122,240","124,240","124,240","126,240"]}

但是，当我快速绘制时，我得到了所需的图形，但缺少很多坐标值

{"XY":["96,320","117,302","170,262","252,208"]}

下面是我用来实现这个的代码

@implementation PJRSignatureView
{
    UIBezierPath *beizerPath;
    UIImage *incrImage;
    CGPoint points[10];
    uint control;
}
- (void)drawRect:(CGRect)rect
{
    [incrImage drawInRect:rect];
    [beizerPath stroke];

    // Set initial color for drawing

    UIColor *fillColor = INITIAL_COLOR;
    [fillColor setFill];
    UIColor *strokeColor = INITIAL_COLOR;
    [strokeColor setStroke];
    [beizerPath stroke];

}

- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event
{
    if ([lblSignature superview]){
        [lblSignature removeFromSuperview];
    }
    rectArray = [[NSMutableArray alloc] init];
    control = 0;
    UITouch *touch = [touches anyObject];
    points[0] = [touch locationInView:self];

    CGPoint startPoint = points[0];
    CGPoint endPoint   = CGPointMake(startPoint.x + 1.5, startPoint.y
                              + 2);



   [beizerPath moveToPoint:startPoint];
        NSLog(@"myPoint = %@", [NSValue valueWithCGPoint:endPoint]);
        NSLog(@"beizerPath    :%@",beizerPath);
    [beizerPath addLineToPoint:endPoint];
     NSLog(@"beizerPath end:%@",beizerPath);
}

- (void)touchesMoved:(NSSet *)touches withEvent:(UIEvent *)event
{
    UITouch *touch = [touches anyObject];
    CGPoint touchPoint = [touch locationInView:self];
    control++;
    points[control] = touchPoint;

    if (control == 4)
    {
        points[3] = CGPointMake((points[2].x + points[4].x)/2.0, (points[2].y + points[4].y)/2.0);

        [beizerPath moveToPoint:points[0]];
        [beizerPath addCurveToPoint:points[3] controlPoint1:points[1] controlPoint2:points[2]];

        [self setNeedsDisplay];

        points[0] = points[3];
        points[1] = points[4];
        control = 1;
    }
       NSLog(@"beizerPathmove:%@",beizerPath);
    NSString *rect_xy = [NSString stringWithFormat:@"%.f,%.f",touchPoint.x,touchPoint.y];

    [rectArray addObject:rect_xy];
}

- (void)touchesEnded:(NSSet *)touches withEvent:(UIEvent *)event
{
    [self drawBitmapImage];
    [self setNeedsDisplay];
    [beizerPath removeAllPoints];

    NSMutableDictionary *rectDict = [[NSMutableDictionary alloc]init];
    [rectDict setValue:rectArray forKey:@"XY"];
    NSData *jsonData = [NSJSONSerialization dataWithJSONObject:rectDict options:0 error:nil];

    // Checking the format
    NSLog(@"%@",[[NSString alloc] initWithData:jsonData encoding:NSUTF8StringEncoding]);
    control = 0;
}

---

如何在快速绘制时找到所有坐标值？

系统以一定间隔发送触摸事件。如果你走得慢，你会得到更多，但走得快，你会得到更少。如果你行动迅速，你就得不到更多。但你可能也不需要更多。你只需要在点之间画一条线，不管它们之间的距离是小是大。

苹果产品以一定的间隔发送触摸事件。因此，如果你画/写任何东西都很慢，你就有可能得到所有的坐标值，如果你画/写得很快，你就会少画一些坐标值。并在web中应用您使用过的相同功能。希望现在可以解决此问题。

可能是您的代码降低了触摸处理程序的速度，因此丢失了事件。首先在

touchesend

中删除

jsonData

的创建，看看这是否会改善情况。@特洛伊木马甚至我尝试了touchesend之外的json数据，但得到了相同的结果。并且我NSLog字符串值rect_xy（即使在该坐标上）丢失。即使在添加称为“RECTARRY”的数组之前，用于字符串“rect_xy”的NSLog也丢失。是否有任何方法可以在特定间隔控制系统触摸事件？否。您无法更改系统发送触摸事件的间隔。但你为什么需要更多？也许你的问题还有另一个解决方案。实际上，该应用程序将向用户显示MQTT服务器速度。所以，用户绘制的任何东西都应该显示在网页上，如果我得到了所有的坐标，那么它就会工作。如果坐标值遗漏了仅在网络上显示的虚线。好吧，和你在iOS上做的一样，你必须在网络上做：-在点之间画一条线，而不仅仅是画点。