Ios 执行按操作通知Swift

我使用Firebase通知发送和接收远程通知

当我收到通知时，我也会收到一个ID，让我能够识别一个特定的“帖子”

现在，当我单击notification时，我需要该应用程序打开一个viewController，将接收到的ID传递给它，以便启动一个加载“post”信息的方法（在

viewDidLoad（）

）

以下是通知代码：

    func application(_ application: UIApplication, didReceiveRemoteNotification userInfo: [AnyHashable: Any],
                 fetchCompletionHandler completionHandler: @escaping (UIBackgroundFetchResult) -> Void) {
    // Print message ID.
    print("Message ID: \(userInfo["gcm.message_id"]!)")

    let aps = userInfo["aps"] as! NSDictionary
    let body_notifica = aps["alert"]! as! NSDictionary
    let titolo_notifica = body_notifica["title"]! as! String
    let testo_notifica = body_notifica["body"]! as! String

    let id_lavoro = userInfo["id_lavoro"]! //THIS IS THE ID I NEED TO PASS TO VIEW CONTROLLER

    if application.applicationState == UIApplicationState.inactive || application.applicationState == UIApplicationState.background{
        let viewController = self.window!.rootViewController!.storyboard!.instantiateViewController(withIdentifier: "annuncio_view_controler")
        viewController.performSegue(withIdentifier: "a", sender: <#T##Any?#>)
    }


    let banner = Banner(title: titolo_notifica, subtitle: testo_notifica, image: UIImage(named: "Info"), backgroundColor: UIColor(red:0.0/255.0, green:0.0/255.0, blue:0.0/255.0, alpha:0.5))
    banner.dismissesOnTap = true
    banner.show(duration: 3.0)

    print(userInfo)

}

func应用程序（application:UIApplication，DidReceiveMemoteNotification用户信息：[AnyHashable:Any]，
fetchCompletionHandler completionHandler:@escaping（UIBackgroundFetchResult）->Void{
//打印消息ID。
打印（“消息ID:\（userInfo[“gcm.Message\u ID”！））
让aps=userInfo[“aps”]作为！NSDictionary
让body_notifica=aps[“alert”]！as！NSDictionary
让titolo_notifica=body_notifica[“title”]！as！字符串
设testo_notifica=body_notifica[“body”]！as！字符串
让id\u lavoro=userInfo[“id\u lavoro”]！//这是我需要传递给视图控制器的id
如果application.applicationState==UIApplicationState.inactive | | application.applicationState==UIApplicationState.background{
让viewController=self.window！.rootViewController！.storyboard！。实例化viewController（标识符为：“annuncio\u view\u controller”）
viewController.PerformScheue（标识符为“a”，发送方为：）
}
let banner=banner（标题：titolo_notifica，副标题：testo_notifica，图片：UIImage（名为：“Info”），背景色：UIColor（红色：0.0/255.0，绿色：0.0/255.0，蓝色：0.0/255.0，阿尔法：0.5））
banner.dismissentap=true
旗帜秀（持续时间：3.0）
打印（用户信息）
}

---

谢谢你们

您可以使用这个代码示例来处理这个问题

func application(_ application: UIApplication, didReceiveRemoteNotification userInfo: [AnyHashable: Any], fetchCompletionHandler completionHandler: @escaping (UIBackgroundFetchResult) -> Void) {


    if ( application.applicationState == .inactive || application.applicationState == .background){

        //handle tapping on push notification and here you can open needed controller
    }
}

要确切知道需要打开哪个控制器，需要在控制器层次结构上查看

就我而言

   `guard let rootViewController = self.window?.rootViewController as? TabBarVC else {
        return
    }
    // select second tab
    rootViewController.selectedIndex = 1

    guard let navigationController = rootViewController.selectedViewController as? UINavigationController else {
        return
    }

`

编辑：我尝试过这个，但什么都没有

if application.applicationState == UIApplicationState.inactive || application.applicationState == UIApplicationState.background{
        let viewController = self.window!.rootViewController!.storyboard!.instantiateViewController(withIdentifier: "home_view_controller") as! HomeViewController

        viewController.toPassId = id_lavoro!
        viewController.performSegue(withIdentifier: "segue_annuncio_profilo", sender: self)

    }

如何检查层次结构？我的视图不是TabBar的视图，它可以从很多视图打开（也在TabBar中）

多亏了@Vadim Kozak

 if application.applicationState == UIApplicationState.inactive || application.applicationState == UIApplicationState.background{
        guard let rootViewController = self.window?.rootViewController as? UITabBarController else {
            return
        }
        // select second tab
        rootViewController.selectedIndex = 1

        guard let navigationController = rootViewController.selectedViewController as? UINavigationController else {
            return
        }


        let viewController = self.window!.rootViewController!.storyboard!.instantiateViewController(withIdentifier: "annuncio_view_controler") as! LavoroViewController

        viewController.id_lavoro = id_lavoro!

        rootViewController.present(viewController, animated: true, completion: nil)


    }

---

好啊但是如何设置该视图的ID？我需要一个类似的“prepare（for:segue）…

viewController.your_id=id\u lavoro

如果运行代码，会发生什么

let viewController=self.window！.rootViewController！.storyboard！。instanceviewcontroller（带有标识符：“home\u view\u controller”）as！HomeViewController viewController.toPassId=id\u lavoro！viewController.performsgue（带有标识符：“segue\u annuncio\u profilo”，发件人：self）

不明白您在做什么，为什么要执行？