Ios 以NSDictionary作为对象的嵌套数组上的NSPredicate

我有一本字典，比如：

{
"2017-05-02" =     (
            {
        "always_valid" = 0;
        date = "2017-05-02";
        from = "12:00";
        to = "13:00";
    },
            {
        "always_valid" = 0;
        date = "2017-05-02";
        from = "12:00";
        to = "12:00";
    },
            {
        "always_valid" = 0;
        date = "2017-05-02";
        from = "14:00";
        "hourly_rate" = 12;
        to = "15:00";
    }
);
"2017-05-03" =     (
            {
        "always_valid" = 0;
        date = "2017-05-03";
        from = "12:00";
        to = "13:00";
    }
);
"2017-05-18" =     (
            {
        "always_valid" = 1;
        date = "2017-05-18";
        from = "12:00";
        to = "12:00";
    }
);
}

我正在申请

NSPredicate *filter = [NSPredicate predicateWithFormat:@"always_valid = \"1\""];
 NSArray *alwaysvalid = [[dic allValues] filteredArrayUsingPredicate:filter];

当我有这样的结构时，它就起作用了

数组>字典

但现在就像

数组>数组>字典

通过对数组执行[dic allValues]。 任何帮助我应该应用什么来保持快速。

尝试以下方法：

 NSArray *array = [NSArray arrayWithObject:dict];   // you can also do same for Name key... 
 NSArray *alwaysvalid = [array filteredArrayUsingPredicate:filter];

---

您需要做的是枚举字典并创建新的筛选字典

NSMutableDictionary *filterDic = [[NSMutableDictionary alloc] init];
NSPredicate *filter = [NSPredicate predicateWithFormat:@"always_valid = 1"];
[dict enumerateKeysAndObjectsUsingBlock:^(NSString* key, NSArray* obj, BOOL *stop) {
     NSArray *filterArray = [obj filteredArrayUsingPredicate:filter];
     if (filterArray.count > 0) {
         filterDic[key] = filterArray;
     }
}];

---

我应该返回“2017-05-18”=（{“始终有效”=1；date=“2017-05-18”；from=“12:00”；to=“12:00”；}）；由于未捕获的异常“NSInvalidArgumentException”而终止应用程序，原因：“ALL或ANY运算符的左侧必须是NSArray或NSSet。”；NSArray*alwaysvalid=[[dic allValues]filteredArrayUsingPredicate:filter]；“始终有效”将始终为1或0。@SameerAzem您是否尝试过使用

EnumerateKeysandObjectsSusingBlock

？@SameerAzem我不明白，因为如果您的字典包含所有值作为数组，这应该可以很好地工作