Ios 如何使Http get请求URL由swift 3中的管道组成?
我收到了swift 3的get请求。该url具有管道。如果没有管道,它可以正常工作,但是当我添加管道时,代码会在展开可选值错误时中断,说find nil 这是我的网址 让url=url(字符串:“”) 这是我的密码:Ios 如何使Http get请求URL由swift 3中的管道组成?,ios,swift,http-get,Ios,Swift,Http Get,我收到了swift 3的get请求。该url具有管道。如果没有管道,它可以正常工作,但是当我添加管道时,代码会在展开可选值错误时中断,说find nil 这是我的网址 让url=url(字符串:“”) 这是我的密码: func synchronusGetRequstForExternalAPI(api_url:String, headers:[ String: String]) -> ResultModel { let resultModel = ResultModel(
func synchronusGetRequstForExternalAPI(api_url:String, headers:[ String: String]) -> ResultModel {
let resultModel = ResultModel()
//create the url with URL
let url = URL(string:"https://maps.googleapis.com/maps/api/directions/json?origin=colombo&destination=kandy&waypoints=optimize:true|&key=AIzaSyCNBcQLIVvNwqjkYiLawnYK_OK4EQbRM5M")
//create the URLRequest object using the url object
var request = URLRequest(url: url!)
//set headers
for item in headers {
request.addValue(item.value, forHTTPHeaderField: item.key)
}
let semaphore = DispatchSemaphore(value: 0)
let task = URLSession.shared.dataTask(with: request as URLRequest) {
(data, response, error) in
if(error != nil){
resultModel.ErrorType = .NO_INT
resultModel.JsonReslut = JSON.null
}else{
if let resp = response as? HTTPURLResponse{
if(resp.statusCode == 200){
if let jsonResult = JSON(data) as? JSON {
resultModel.ErrorType = .NO_ERROR
resultModel.JsonReslut = jsonResult
}
}else{
if let jsonResult = JSON(data) as? JSON {
resultModel.ErrorType = .SEREVR_ERROR
resultModel.JsonReslut = jsonResult
}else{
resultModel.ErrorType = .SEREVR_ERROR
resultModel.JsonReslut = JSON.null
}
}
}
}
semaphore.signal()
}
task.resume()
_ = semaphore.wait(timeout: DispatchTime.distantFuture)
return resultModel
}
有人能告诉我为什么会发生这种情况吗?
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是URL中不允许的字符。尝试转义URL字符串
let url = URL(string:"https://maps.googleapis.com/maps/api/directions/json?origin=colombo&destination=kandy&waypoints=optimize:true|&key=AIzaSyCNBcQLIVvNwqjkYiLawnYK_OK4EQbRM5M".stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLFragmentAllowedCharacterSet()))
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不是URL中允许的字符。尝试转义URL字符串
let url = URL(string:"https://maps.googleapis.com/maps/api/directions/json?origin=colombo&destination=kandy&waypoints=optimize:true|&key=AIzaSyCNBcQLIVvNwqjkYiLawnYK_OK4EQbRM5M".stringByAddingPercentEncodingWithAllowedCharacters(NSCharacterSet.URLFragmentAllowedCharacterSet()))