Ios 输入ApplicationIDBecMeactive时本地通知不起作用

我使用重复本地标记向用户显示警报。为此，我使用了下面的代码

UILocalNotification* localNotification = [[UILocalNotification alloc] init];
localNotification.fireDate = [[NSDate date] dateByAddingTimeInterval:60];
localNotification.alertBody = @"sss";
localNotification.alertAction = @"Show me the item";
localNotification.timeZone = [NSTimeZone defaultTimeZone];
localNotification.applicationIconBadgeNumber = [[UIApplication sharedApplication] applicationIconBadgeNumber] + 1;
[[UIApplication sharedApplication] scheduleLocalNotification:localNotification];

使用NSNotification Center，我将每60秒呼叫一次本地通知。它工作得很好

在Appdelegate中，我还使用以下代码：-

 - (void)application:(UIApplication *)application didReceiveLocalNotification:(UILocalNotification *)notification
    {
        NSLog(@"Received");
        UIApplicationState state = [application applicationState];
        if (state == UIApplicationStateActive) {

             [[NSNotificationCenter defaultCenter] postNotificationName:@"RestartProcess" object:self];

}
 application.applicationIconBadgeNumber = 0;
}

也

我的问题是，当本地通知启动时，我按下home按钮，然后等待显示。时间段结束后，显示一条通知消息。

---

当我单击应用程序图标时，进程停止。在此之后，本地通知不起作用。但当我单击通知消息时，它将正常工作。我如何解决此问题。有人可以帮助我做到这一点吗。提前感谢。

只有当您点击通知消息页面时，才会调用didReceiveLocalNotification。如果要在ApplicationIDBecomeActive中执行此操作，必须手动执行

您可以检查徽章编号计数（如果通知包含徽章），如：

---

按主页按钮时：

UIApplicationState state = [application applicationState];
// at this time, state == UIApplicationStateInactive

当您单击应用程序时，我认为您应该使用以下方法实现：

- (void)applicationDidBecomeActive:(UIApplication *)application- (void)applicationWillEnterForeground:(UIApplication *)application
{
 UIApplicationState state = [application applicationState];
 application.applicationIconBadgeNumber = 0;
 //state at this time is UIApplicationStateInactive
 if (state == UIApplicationStateInactive) {   
    [[NSNotificationCenter defaultCenter] postNotificationName:@"RestartProcess" object:self];
 }
}

希望这对你有帮助

UIApplicationState state = [application applicationState];
// at this time, state == UIApplicationStateInactive

- (void)applicationDidBecomeActive:(UIApplication *)application- (void)applicationWillEnterForeground:(UIApplication *)application
{
 UIApplicationState state = [application applicationState];
 application.applicationIconBadgeNumber = 0;
 //state at this time is UIApplicationStateInactive
 if (state == UIApplicationStateInactive) {   
    [[NSNotificationCenter defaultCenter] postNotificationName:@"RestartProcess" object:self];
 }
}