Ios 在swift中,Float值以双引号从[String:AnyObject]返回
当我使用Ios 在swift中,Float值以双引号从[String:AnyObject]返回,ios,swift,swift3,floating-point,anyobject,Ios,Swift,Swift3,Floating Point,Anyobject,当我使用[String:AnyObject]时,我不知道为什么浮点值总是带有双引号。你们有什么方法可以让我得到正确的结果吗 let appliedLoyalty: Float = 1.05 let appliedWallet: Float = 0.55 let payLoad: [String: AnyObject] = ["custid": custid! as AnyObject, "discounts": ["loyalty": appliedLoyalty,"wallet": appl
[String:AnyObject]
时,我不知道为什么浮点值总是带有双引号。你们有什么方法可以让我得到正确的结果吗
let appliedLoyalty: Float = 1.05
let appliedWallet: Float = 0.55
let payLoad: [String: AnyObject] = ["custid": custid! as AnyObject, "discounts": ["loyalty": appliedLoyalty,"wallet": appliedWallet] as AnyObject] // custid is string value
print(payLoad)
当我打印有效负载时,浮点值用双引号引起来
["discounts": {
"loyalty" = "1.05";
"wallet" = "0.45";
}, "custid": "puma"]
使用print(payLoad)
时,将调用字典的description
方法。description
方法的实现与控制台上打印的相同。您应该使用JSONSerialization
查看实际的json,而不是打印字典。使用下面的代码或使用断点检查负载中存储的内容
let jsonData = try? JSONSerialization.data(withJSONObject: payLoad, options: .prettyPrinted)
let jsonStr = String(data: jsonData!, encoding: .utf8)
print(jsonStr!)
使用print(payLoad)
时,将调用字典的description
方法。description
方法的实现与控制台上打印的相同。您应该使用JSONSerialization
查看实际的json,而不是打印字典。使用下面的代码或使用断点检查负载中存储的内容
let jsonData = try? JSONSerialization.data(withJSONObject: payLoad, options: .prettyPrinted)
let jsonStr = String(data: jsonData!, encoding: .utf8)
print(jsonStr!)
将任何对象替换为以下类似对象:
let appliedLoyalty: Float = 1.05
let appliedWallet: Float = 0.55
let custID = "puma"
let payLoad: [String: Any] = ["custid": custID, "discounts": ["loyalty": appliedLoyalty,"wallet": appliedWallet]] // custid is string value
print(payLoad)
将任何对象替换为以下类似对象:
let appliedLoyalty: Float = 1.05
let appliedWallet: Float = 0.55
let custID = "puma"
let payLoad: [String: Any] = ["custid": custID, "discounts": ["loyalty": appliedLoyalty,"wallet": appliedWallet]] // custid is string value
print(payLoad)
感谢您宝贵的回答。它工作得很好。非常感谢@ivarunth,不需要强制转换(
“puma”作为字符串
,而作为字典中的任何
强制转换),类型推断可以完成它的工作,尤其是在处理如此简单的类型时。@DávidPásztor你说得对。。按照你说的,我已经更新了答案。谢谢:)谢谢你宝贵的回答。它工作得很好。非常感谢@ivarunth,不需要强制转换(“puma”作为字符串
,而作为字典中的任何
强制转换),类型推断可以完成它的工作,尤其是在处理如此简单的类型时。@DávidPásztor你说得对。。按照你说的,我已经更新了答案。谢谢:)