Ios 在Swift 3中读取JSON文件时出错
我在swift 2.2中的所有项目中都使用了这段代码,但当我在将xcode更新为xcode 8后创建新项目时,我在用这段代码读取JSON文件时遇到了这个问题Ios 在Swift 3中读取JSON文件时出错,ios,swift,swift3,xcode8,Ios,Swift,Swift3,Xcode8,我在swift 2.2中的所有项目中都使用了这段代码,但当我在将xcode更新为xcode 8后创建新项目时,我在用这段代码读取JSON文件时遇到了这个问题 do { let comURL = "mylinkhere"+"customer_key=\(self.customer_key)" // NSLog("PostData: %@",post) let regURL:NSURL = NSURL(string: comURL)!
do {
let comURL = "mylinkhere"+"customer_key=\(self.customer_key)"
// NSLog("PostData: %@",post)
let regURL:NSURL = NSURL(string: comURL)!
//let postData:NSData = post.dataUsingEncoding(NSASCIIStringEncoding)!
//let postLength:NSString = String( postData.length )
let request:NSMutableURLRequest = NSMutableURLRequest(url: regURL as URL)
request.httpMethod = "POST"
//request.HTTPBody = postData
//request.setValue(postLength as String, forHTTPHeaderField: "Content-Length")
request.setValue("application/x-www-form-urlencoded", forHTTPHeaderField: "Content-Type")
request.setValue("application/json", forHTTPHeaderField: "Accept")
var reponseError: NSError?
var response: URLResponse?
var urlData: NSData?
do {
urlData = try NSURLConnection.sendSynchronousRequest(request as URLRequest, returning:&response) as NSData?
// print(urlData)
} catch let error as NSError {
reponseError = error
urlData = nil
}
if ( urlData != nil ) {
let res = response as! HTTPURLResponse!;
//NSLog("Response code: %ld", res?.statusCode);
if ((res?.statusCode)! >= 200 && (res?.statusCode)! < 300)
{
let responseData:NSString = NSString(data:urlData! as Data, encoding:String.Encoding.utf8.rawValue)!
NSLog("Response Data ==> %@", responseData );
//var error: NSError?
let jsonData = try JSONSerialization.jsonObject(with: urlData! as Data, options: .allowFragments) as! [String:AnyObject]
self.Appstatus = (jsonData as AnyObject).value("android_app_status") as! NSString
self.StreamURL = (jsonData as AnyObject).value("android_streaming_url") as! NSString
//[jsonData[@"success"] integerValue];
// NSLog("App Status2: %@", self.Appstatus);
// NSLog("App Stream URL2: %@", self.StreamURL);
if(self.Appstatus == "true")
{
}
else{
}
}
} else {
let alertView:UIAlertView = UIAlertView()
alertView.title = "Sign in Failed!"
alertView.message = "Connection Failure"
if let error = reponseError {
alertView.message = (error.localizedDescription)
}
alertView.delegate = self
alertView.addButton(withTitle: "OK")
alertView.show()
}
} catch {
let alertView:UIAlertView = UIAlertView()
alertView.title = "Sign Up Failed!"
alertView.message = "Server Error!"
alertView.delegate = self
alertView.addButton(withTitle: "OK")
alertView.show()
}
错误是:
您不必将jsonData类型转换为任何对象,正如我从代码中看到的,这是一个类型为[String:AnyObject]的字典。如果你想从JSONDATA打开一个字符串,我建议你考虑下面的代码。
if let appStatus = jsonData["android_app_status"] as? NSString{
self.AppStatus = appStatus
}
通过这种安全的解包,你可以确保你的程序不会崩溃,即使字典没有“android应用程序状态”键
希望这有帮助。在Swift 3中,大多数
AnyObject
类型已更改为Any
基本上是用Swift
- 不要使用
获取字典键的值,请使用键订阅valueForKey
- 在将类型向下转换后,不要将其向上转换(
),这样会产生相反的效果作为AnyObject
字符串
let jsonData = try JSONSerialization.jsonObject(with: urlData! as Data, options: .allowFragments) as! [String:Any]
self.Appstatus = jsonData["android_app_status"] as! String
self.StreamURL = jsonData["android_streaming_url"] as! String
最后,不要使用不推荐的同步URL加载API。显示您的json响应。如下:响应数据==>{“android\u streaming\u URL”:“link”,“ios\u streaming\u URL”:“link”,“android\u app\u status”:“true”,“ios\u app\u status”:“true”}如果您将
[String:AnyObject]
,那么之后为什么要将jsonData作为AnyObject
?所以试试self.Appstatus=(jsondataas[String:AnyObject])。value(“android\u app\u status”)as!NSString它不起作用,但我试过这样做,现在它可以自己工作了。Appstatus=jsonData[“ios\u app\u status”]as!字符串作为NSStringI尝试了这一点,现在它工作了,谢谢你self.Appstatus=jsonData[“ios\u app\u status”]as!NSStringI写的字符串:不要使用基金会<代码> NString < /C>。拆下第二个铸件
let jsonData = try JSONSerialization.jsonObject(with: urlData! as Data, options: .allowFragments) as! [String:Any]
self.Appstatus = jsonData["android_app_status"] as! String
self.StreamURL = jsonData["android_streaming_url"] as! String