GCM iOS可以'；t转换接收到的消息对象

我正在使用用于iOS的GCM，收到我推送的消息，但消息看起来像以下对象：

[aps: {
    alert =     {
        body = "great match!";
        title = "Portugal vs. Denmark";
    };
}, gcm.message_id: 0:1464264430528872......]

以下是我收到消息时调用的整个函数：

 func application( application: UIApplication,
                      didReceiveRemoteNotification userInfo: [NSObject : AnyObject],
                                                   fetchCompletionHandler handler: (UIBackgroundFetchResult) -> Void) {
        print("Notification received: \(userInfo)")
        print(userInfo)
        // This works only if the app started the GCM service
        GCMService.sharedInstance().appDidReceiveMessage(userInfo);
        // Handle the received message
        // Invoke the completion handler passing the appropriate UIBackgroundFetchResult value
        // [START_EXCLUDE]
        NSNotificationCenter.defaultCenter().postNotificationName(messageKey, object: nil,
                                                                  userInfo: userInfo)
        handler(UIBackgroundFetchResult.NoData);
        // [END_EXCLUDE]
    }

---

我找不到如何获取警报正文和警报标题如何才能做到这一点？

userInfo

是[NSObject:AnyObject]类型的字典。要访问这些值，请使用订阅

“aps”键包含一个包含字典的字典，因此，例如，您可以执行以下操作：

if let aps = userInfo["aps"] as? [String:[String:String]],
        alert = aps["alert"],
        body = alert["body"],
        title = alert["title"] {
    print(title)
    print(body)
}