线程1:EXC\u错误访问(代码=1,地址=)ios

线程1:EXC\u错误访问(代码=1,地址=)ios,ios,nszombie,Ios,Nszombie,我在iOS模拟器(6和7)上一直面临这个问题。尝试重置手机,但出现相同问题 加载其他视图控制器时出现此错误 # Event Type ∆ RefCt RefCt Timestamp Responsible Library Responsible Caller 0 Malloc +1 1 00:33.396.540 UIKit UINibDecoderDecodeObjectForValue 1 Retain +1 2 00:33.397.009

我在iOS模拟器(6和7)上一直面临这个问题。尝试重置手机,但出现相同问题

加载其他视图控制器时出现此错误

#   Event Type  ∆ RefCt RefCt   Timestamp   Responsible Library Responsible Caller
0   Malloc  +1  1   00:33.396.540   UIKit   UINibDecoderDecodeObjectForValue
1   Retain  +1  2   00:33.397.009   UIKit   -[UIRuntimeConnection initWithCoder:]
2   Retain  +1  3   00:33.397.047   UIKit   UINibDecoderDecodeObjectForValue
3   Retain  +1  4   00:33.397.064   UIKit   UINibDecoderDecodeObjectForValue
    Retain/Release (2)          00:33.397.537   UIKit   -[UIViewController setView:]
6   Retain  +1  5   00:33.397.548   UIKit   -[UINib instantiateWithOwner:options:]
7   Release -1  4   00:33.397.592   UIKit   -[UINibDecoder finishDecoding]
    Release (2) -2      00:33.397.647   UIKit   -[UINibDecoder finishDecoding]
10  Release -1  1   00:33.397.712   UIKit   -[UIRuntimeConnection dealloc]
11  Release -1  0   00:33.409.138   UIKit   _UIApplicationHandleEvent
12  Zombie      -1  00:35.524.392   UIKit   ___updateViewDependenciesForConstraint_block_invoke_0
已尝试探查器,僵尸出现以下错误,但无法进一步处理。有人能指导下一步吗

已将Objective-C消息发送到解除分配的
UIView
对象(僵尸),地址为:
0xbede440

updateViewDependenciesForConstraint_block_invoke_0+0x4d"
+0x3f   movl                2704706(%edi), %ecx
+0x45   movl                %eax, 8(%esp)
+0x49   movl                %ecx, 4(%esp)
+0x4d   movl                %esi, (%esp)
+0x50   calll               "DYLD-STUB$$objc_msgSend"
+0x55   addl                $16, %esp
+0x58   popl                %esi`enter code here`
+0x59   popl                %edi
+0x5a   popl                %ebp
+0x5b   ret  
+0x5c   nopl                (%eax)
示例代码

#pragma mark UITableViewDelegate

- (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)tableIndexPath {  

//Logic for validation 
XXXXXXXXXXx

[self performSegueWithIdentifier:@"ADDXXXX" sender:self];
        return;

}

-(void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender{
    if ([[segue identifier] isEqualToString:@"ADDXXXX"]){
        ADDXXXX *myVC = [segue destinationViewController];
        myVC.setXXX
        NSLog(@"INIT %p", self);    
    }
}

好的,我们可以通过在堆栈溢出中引用这个线程来解决它。谢谢大家的回复


提供更多信息-尝试了以上步骤后得出了此僵尸声明。需要帮助来理解和解决我的问题-更新了我的问题的细节。打开另一个视图控制器时出错。您可以在显示另一个视图控制器的位置发布代码吗