谷歌登录iOS漏洞
我正在尝试在我的iOS应用程序中实现GoogleAuth 我在appDelegate中,我正在尝试实现这个函数谷歌登录iOS漏洞,ios,swift,google-signin,Ios,Swift,Google Signin,我正在尝试在我的iOS应用程序中实现GoogleAuth 我在appDelegate中,我正在尝试实现这个函数 func application(application: UIApplication, openURL url: NSURL, options: [String: AnyObject]) -> Bool { return GIDSignIn.sharedInstance().handleURL(url as URL!, sourceApplication: opti
func application(application: UIApplication, openURL url: NSURL, options: [String: AnyObject]) -> Bool
{
return GIDSignIn.sharedInstance().handleURL(url as URL!, sourceApplication: options[UIApplicationOpenURLOptionsSourceApplicationKey] as? String, annotation: options[UIApplicationOpenURLOptionsAnnotationKey])
}
函数的这一部分出现错误:
options[UIApplicationOpenURLOptionsSourceApplicationKey] as? String
错误是
我不知道发生了什么事。有人能帮我吗?尝试将
注释:选项[UIApplicationOpenUrlOptions注释键]
更改为注释:选项[UIApplicationOpenUrlOptions注释键]?字符串
尝试将注释:选项[UIApplicationOpenUrlOptions注释键]
更改为注释:选项[UIApplicationOpenUrlOptions注释键]?字符串
请尝试使用您的代码:
请尝试使用您的代码来执行以下操作:)
下面是一个奇妙的答案:
func application(_ app: UIApplication,
open url: URL,
options: [UIApplicationOpenURLOptionsKey : Any] = [:]) -> Bool {
return GIDSignIn.sharedInstance().handle(url as URL!,
sourceApplication: options[UIApplicationOpenURLOptionsKey.sourceApplication] as! String!,
annotation: options[UIApplicationOpenURLOptionsKey.annotation])
}
参考自
这里有一个奇妙的答案:
func application(_ app: UIApplication,
open url: URL,
options: [UIApplicationOpenURLOptionsKey : Any] = [:]) -> Bool {
return GIDSignIn.sharedInstance().handle(url as URL!,
sourceApplication: options[UIApplicationOpenURLOptionsKey.sourceApplication] as! String!,
annotation: options[UIApplicationOpenURLOptionsKey.annotation])
}
参考自
这并没有解决问题。你认为问题是什么?那没解决。你认为问题是什么?
func application(_ app: UIApplication,
open url: URL,
options: [UIApplicationOpenURLOptionsKey : Any] = [:]) -> Bool {
return GIDSignIn.sharedInstance().handle(url as URL!,
sourceApplication: options[UIApplicationOpenURLOptionsKey.sourceApplication] as! String!,
annotation: options[UIApplicationOpenURLOptionsKey.annotation])
}