如何为联系人创建iOS共享扩展

如何为联系人创建iOS共享扩展,ios,swift,ios8-share-extension,Ios,Swift,Ios8 Share Extension,我正在尝试使用以下代码创建iOS共享扩展以共享联系人: let contactType = "public.vcard" override func viewDidLoad() { let items = extensionContext?.inputItems var itemProvider: NSItemProvider? if items != nil && items!.isEmpty == false { let item

我正在尝试使用以下代码创建iOS共享扩展以共享联系人:

let contactType = "public.vcard"

override func viewDidLoad() {
    let items = extensionContext?.inputItems
    var itemProvider: NSItemProvider?

    if items != nil && items!.isEmpty == false {
        let item = items![0] as! NSExtensionItem
        if let attachments = item.attachments {
            if !attachments.isEmpty {
                itemProvider = attachments[0] as? NSItemProvider
            }
        }
    }

    if itemProvider?.hasItemConformingToTypeIdentifier(contactType) == true {
        itemProvider?.loadItemForTypeIdentifier(contactType, options: nil) { item, error in
            if error == nil { 
                print("item: \(item)")
            }
        }
    }
}
我得到以下输出:

item: Optional(<42454749 4e3a5643 4152440d 0a564552 53494f4e 3a332e30 0d0a5052 4f444944 3a2d2f2f 4170706c 6520496e 632e2f2f 6950686f 6e65204f 5320392e 322f2f45 4e0d0a4e 3a42656e 6e657474 3b436872 69733b3b 3b0d0a46 4e3a2043 68726973 20204265 6e6e6574 74200d0a 54454c3b 74797065 3d484f4d 453b7479 70653d56 4f494345 3b747970 653d7072 65663a28 36313529 c2a03432 352d3637 31390d0a 454e443a 56434152 440d0a>)
项:可选()

如果设置断点,我会看到该项具有NSSecureCodeding类型。我的问题是如何将其转换为CNContact?

您获得的物品类型为
NSData
。您必须将其转换为
字符串
,才能获得vCard字符串:

if itemProvider?.hasItemConformingToTypeIdentifier(contactType) == true {
    itemProvider?.loadItemForTypeIdentifier(contactType, options: nil) { item, error in
        if error == nil {
            if let data = item as? NSData, let vCardString = String(data: data, encoding: NSUTF8StringEncoding) {
                print(vCardString)
            }
        }
    }
}

更新了@joern对Swift 3的答复:

if itemProvider.hasItemConformingToTypeIdentifier(kUTTypeContact as String) {

    itemProvider.loadItem(forTypeIdentifier: kUTTypeContact as String, options: nil, completionHandler: { (contact, error) in
            if let contactData = contact as? Data, let vCardString = String(data: contactData, encoding: .utf8) {
                print(vCardString)
            }
    })
}
对于操作扩展,您还需要添加
操作队列

if itemProvider.hasItemConformingToTypeIdentifier(kUTTypeContact as String) {

    itemProvider.loadItem(forTypeIdentifier: kUTTypeContact as String, options: nil, completionHandler: { (contact, error) in
        OperationQueue.main.addOperation {
            if let contactData = contact as? Data, let vCardString = String(data: contactData, encoding: .utf8) {
                print(vCardString)
            }
        }
    })
}

当您共享任何联系人时,
itemProvider
包含CNContact。要访问该联系人,您需要将该数据(键入NSSecureCoding)转换为
CNContact

let uttypeContact = kUTTypeContact as String
if itemProvider.hasItemConformingToTypeIdentifier(uttypeContact) {
  itemProvider.loadItemForTypeIdentifier(uttypeContact, options: nil, completionHandler: { (data, error) in

    if error == nil {
      do {
        if let data = data as? NSData {
          let contact = try CNContactVCardSerialization.contactsWithData(data)
          print(contact)
        }
      } catch {}
    }
  })
}
[更新]
更多细节

我做了一些事情,但在发布时卡住了。应用程序验证失败并显示错误:Info.plist无效。捆绑包中的键“NSExtensionActivationRule”的值无效,如果您已经执行了相同的操作,请帮助我。提前谢谢。@BhavinTrivedi我没有这个问题。请为您的问题添加新问题。