Ios 如何将NSArray转换为特定字符串?
我正在使用Ios 如何将NSArray转换为特定字符串?,ios,swift,nsstring,nsarray,Ios,Swift,Nsstring,Nsarray,我正在使用facebookapi获取用户的朋友。代码如下: let params = ["fields": "id"] let request = FBSDKGraphRequest(graphPath: "me/friends", parameters: params) request.startWithCompletionHandler { (connection : FBSDKGraphRequestConnection!, result : AnyObject!, error : NSE
facebookapi
获取用户的朋友。代码如下:
let params = ["fields": "id"]
let request = FBSDKGraphRequest(graphPath: "me/friends", parameters: params)
request.startWithCompletionHandler { (connection : FBSDKGraphRequestConnection!, result : AnyObject!, error : NSError!) -> Void in
if error != nil {
let errorMessage = error.localizedDescription
print(errorMessage)
/* Handle error */
}
else if result.isKindOfClass(NSDictionary){
/* handle response */
let defaults = NSUserDefaults.standardUserDefaults()
let resultdict = result as! NSDictionary
let data : NSArray = resultdict.objectForKey("data") as! NSArray
for i in 0..<data.count {
let valueDict : NSDictionary = data[i] as! NSDictionary
let id = valueDict.objectForKey("id") as! String
print("the id value is \(id)")
}
let friends = resultdict.objectForKey("data") as! NSArray
print("Found \(friends.count) friends")
print(friends)
defaults.setObject(friends, forKey: "fb_friends")
defaults.synchronize()
}
}
上面的打印
打印(适用于1个fb朋友):
(
{
id=1020XXXXXX305XXX;
}
)
我想将其传递到我的服务器,因此我考虑执行以下操作:
var emptyParams = ["":""]
emptyParams["friends"] = (defaults.objectForKey("fb_friends") as! NSArray).componentsJoinedByString(",")
但是,与params不同的是:
friends: 1020XXXXXX305XXX
我有:
"friends": {
id = 10206503694305180;
}
我想跳过id
并将其作为数组发送,因为在我的服务器上我有:
var friends = req.body.friends;
for(var i=0; i<friends.length; i++) {
console.log(friends[i]);
query = query.or([{ 'fb_friend': friends[i] }]);
}
var-friends=req.body.friends;
对于(var i=0;i根据我对您代码的理解,fb_friends
的类型为[[String:String]]
,您希望将其转换为[String]
您可以使用.map
从字典中获取“id”
let friends = (defaults.objectForKey("fb_friends") as! NSArray)
.map{$0["id"]!}
.joinWithSeparator(",")
let params = [
"friends": friends
]
请给出ResultDisct值。因为我在这里对id值和格式等感到困惑。@Sharpkits我添加了必要的编辑,很抱歉一开始就缺少这些信息!谢谢,但现在它突出显示了映射
,并告诉我,`type(String?)的值没有加入任何成员…:(我目前正在使用Swift 2.2…joinWithSeparator(…
工作得很好,谢谢Bryan!)!
let friends = (defaults.objectForKey("fb_friends") as! NSArray)
.map{$0["id"]!}
.joinWithSeparator(",")
let params = [
"friends": friends
]