iOS-如何将png图像转换为4位位图灰度？

这是事实,

我想使用iOS6+将PNG图像或JPEG转换为4位位图灰度图像，4位位图只需要支持16种灰度

我该怎么办

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提前感谢。

您可以将其转换为8位灰度图像查看，或查看其中包含其他排列，但我无法将其调整为创建4位灰度位图CGBitmapContextCreate，并抱怨它不是有效的参数组合。从理论上讲，CVPixelBuffer下可能会列出4位格式，但我无法让它使用这种技术。

我找到了将图像转换为4位灰度的解决方案，代码如下

-(UIImage *)grayscaleImageAt4Bits:(UIImage *)_image
{
    CGImageRef imageRef = [_image CGImage];
    int width  = CGImageGetWidth(imageRef);
    int height = CGImageGetHeight(imageRef);
    NSInteger _bitsPerComponent = 8;
    NSInteger _bytesPerPixel    = 1;
    NSInteger _bytesPerRow      = _bytesPerPixel * width;
    CGColorSpaceRef colorSpace  = CGColorSpaceCreateDeviceGray();
    uint8_t *sourceData = malloc(height * width * _bytesPerPixel);
    CGContextRef context = CGBitmapContextCreate(sourceData,
                                                 width,
                                                 height,
                                                 _bitsPerComponent,
                                                 _bytesPerRow,
                                                 colorSpace,
                                                 kCGImageAlphaNone);
    CGContextDrawImage(context, CGRectMake(0, 0, width, height), imageRef);

    const int _redIndex   = 0;
    const int _greenIndex = 1;
    const int _blueIndex  = 2;
    int _byteIndex  = 0;
    int _bitIndex   = 0;
    uint8_t *_newImageBits = malloc( height * width * _bytesPerPixel / 2 );
    for(int j=0;j<height;j++)
    {
        for(int k=0;k<width;k++)
        {
            UInt8 _perPixel = _newImageBits[_byteIndex];
            UInt8 *rgbPixel = (UInt8 *) &sourceData[j * width + k];
            int _red   = rgbPixel[_redIndex];
            int _green = rgbPixel[_greenIndex];
            int _blue  = rgbPixel[_blueIndex];
            int _pixelGrayValue = (_green + _red + _blue) / 16;
            UInt8 _pixelByte = (UInt8)_pixelGrayValue;
            _perPixel |= (_pixelByte<<4);
            _newImageBits[_byteIndex] = _perPixel;
            _bitIndex += 4;
            if(_bitIndex > 7)
            {
                _byteIndex++;
                _bitIndex = 0;
            }
        }
    }
    free(sourceData);
    //Direct fetch Bytes of 4-Bits, then you can use this Bytes ( sourceData ) to do something.
    sourceData = _newImageBits;
    CGImageRef cgImage  = CGBitmapContextCreateImage(context);
    UIImage *_grayImage = [UIImage imageWithCGImage:cgImage];
    CGContextRelease(context);
    CGColorSpaceRelease(colorSpace);
    //Convert to NSData type, then you can use this NSData ( _sourceImageData ) to do something.
    NSData *_sourceImageData  = [NSData dataWithBytes:sourceData length:(width * height * _bytesPerPixel)];
    free(sourceData);
    return _grayImage;
}

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而iOS只支持至少8位的颜色显示，所以4位的数据只传输到openGL的纹理中使用

谢谢，我会检查代码是否有意义。谢谢你的回答，我会检查。iOS 8现在发出警告：从枚举类型“enum CGImageAlphaInfo”隐式转换为不同的枚举类型“CGBitmapInfo”又名“enum CGBitmapInfo”