Ios 从视频中捕获静止图像并添加到单独的viewcontroller Swift中的图像视图

我正在尝试从从图像选择器中选择的视频中获取缩略图，并将缩略图添加到单独视图控制器中的UIImageView中，但是，我遇到了错误：

线程1：致命错误：在第二个视图控制器中展开可选值时意外发现nil

@IBOutlet weak var previewImage: UIImageView!


var videourl: URL?


override func viewDidLoad() {
    super.viewDidLoad()

    previewImage.image = thumbnailImageForFileUrl(videourl!) Thread 1: Fatal error: Unexpectedly found nil while unwrapping an Optional value

}

func thumbnailImageForFileUrl(_ fileUrl: URL) -> UIImage? {
    let asset = AVAsset(url: fileUrl)
    let imageGenerator = AVAssetImageGenerator(asset: asset)
    do {
        let thumbnailCGImage = try imageGenerator.copyCGImage(at: CMTimeMake(7, 1), actualTime: nil)
        return UIImage(cgImage: thumbnailCGImage)
    } catch let err {
        print(err)
    }

    return nil
}

我知道错误的意思，只是不明白为什么缩略图没有传递到UIImageView中的下一个视图控制器

这是我的第一个视图控制器代码

    @IBAction func upload(_ sender: Any) {
      let pickerController = UIImagePickerController()
      pickerController.delegate = self
      pickerController.mediaTypes = ["public.movie"]
      present(pickerController, animated: true, completion: nil)  
 }
func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : Any]) {
    if let videoUrl = info[UIImagePickerControllerMediaURL] as? URL {
        self.vidurl = videoUrl
            func prepare(for segue: UIStoryboardSegue, sender: Any?) {
                if segue.identifier == "toupload" {
                    let uploadvc = segue.destination as! UploadVC
                    uploadvc.videourl = vidurl
                }
            }
    if let image = info[UIImagePickerControllerOriginalImage] as? UIImage{
        func prepare(for segue: UIStoryboardSegue, sender: Any?) {
            if segue.identifier == "toupload" {
                let uploadvc = segue.destination as! UploadVC
                uploadvc.previewImage.image = image
            }
        }
    }
    performSegue(withIdentifier: "toupload", sender: nil)
  }
    dismiss(animated: true, completion: nil) 
}

下面是第二个视图控制器的代码

@IBOutlet weak var previewImage: UIImageView!


var videourl: URL?


override func viewDidLoad() {
    super.viewDidLoad()

    previewImage.image = thumbnailImageForFileUrl(videourl!) Thread 1: Fatal error: Unexpectedly found nil while unwrapping an Optional value

}

func thumbnailImageForFileUrl(_ fileUrl: URL) -> UIImage? {
    let asset = AVAsset(url: fileUrl)
    let imageGenerator = AVAssetImageGenerator(asset: asset)
    do {
        let thumbnailCGImage = try imageGenerator.copyCGImage(at: CMTimeMake(7, 1), actualTime: nil)
        return UIImage(cgImage: thumbnailCGImage)
    } catch let err {
        print(err)
    }

    return nil
}

---

当前，您将

prepareforsgue

函数嵌套在选择器的回调中，因此将其删除并在视图控制器的范围内声明，以便在调用performsgue时，将类的videoUrl分配给第二个VC的videoUrl，从而得到非nil。这应该是出来的，并调用performsgue

func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : Any]) {
if let videoUrl = info[UIImagePickerControllerMediaURL] as? URL {
    self.vidurl = videoUrl
  }
  else
  {
   }
    performSegue(withIdentifier: "toupload", sender: nil)

 } 

///

---

贾斯汀，你在网上查过了吗。有大量的文章和教程解释如何通过控制器传递数据。@GuiDupas是的，我搜索过互联网和所有关于使用func prepare（对于segue:UIStoryboardSegue，sender:Any？）函数的内容。所以使用它吧。在类内而不是在方法内创建2个变量，使用方法保存变量上的值并使用

prepare（对于segue:UIStoryboardSegue，sender:Any？

@guidup，因为它起作用了！谢谢。这个很好用。谢谢