Ios 字典比较数组-swift3
我有两套字典。我想写一个函数来比较这两个数组。 仅当主数组包含子数组元素时,函数才应返回true。 否则它应该返回false 这是我的逻辑-Ios 字典比较数组-swift3,ios,arrays,dictionary,predicate,swift3.2,Ios,Arrays,Dictionary,Predicate,Swift3.2,我有两套字典。我想写一个函数来比较这两个数组。 仅当主数组包含子数组元素时,函数才应返回true。 否则它应该返回false 这是我的逻辑- let mainArry = [ ["id":"1","products":["pid": 1, "name": "A", "price": "$5"]], ["id":"3","products":["pid": 3, "name": "B", "price": "$1"]], ["id":"2","products":["pid": 14, "name
let mainArry = [ ["id":"1","products":["pid": 1, "name": "A", "price": "$5"]], ["id":"3","products":["pid": 3, "name": "B", "price": "$1"]], ["id":"2","products":["pid": 14, "name": "C", "price": "$15"]]]
let array1 = [ ["id":"1","products":["pid": 1, "name": "A", "price": "$5"]], ["id":"3","products":["pid": 3, "name": "B", "price": "$1"]]]
let array2 = [ ["id":"1","products":["pid": 1, "name": "A", "price": "$5"]], ["id":"3","products":["pid": 4, "name": "B", "price": "$1"]]]
func compareDictionary(mainArry:[[String: Any]], arr2: [[String: Any]])-> Bool{
let itemsId = arr2.map { $0["id"]! } // 1, 3, 14
let filterPredicate = NSPredicate(format: "id IN %@", itemsId)
let filteredArray = mainArry.filter{filterPredicate.evaluate(with:$0) }
if filteredArray.count != arr2.count {
return false
}
for obj in filteredArray {
let prd = obj as Dictionary<String, Any>
let str = prd["id"] as! String
let searchPredicate = NSPredicate(format: "id == %@", str )
let filteredArr = arr2.filter{searchPredicate.evaluate(with:$0) }
if filteredArr.isEmpty {
return false
}
if !NSDictionary(dictionary: obj["products"] as! Dictionary<String, Any>).isEqual(to: filteredArr.last!["products"] as! [String : Any]) {
return false
}
}
return true
}
let result1 = compareDictionary(mainArry: mainArry, arr2: array1)
let result2 = compareDictionary(mainArry: mainArry, arr2: array2)
print("Result1 = \(result1)") // true
print("Result2 = \(result2)") //false
如果arrayC为空,则表示两个数组相等。我终于得到了它!
我们不需要编写大函数
let mainArry = [ ["id":"1","products":["pid": 1, "name": "A", "price": "$5"]], ["id":"3","products":["pid": 3, "name": "B", "price": "$1"]], ["id":"2","products":["pid": 14, "name": "C", "price": "$15"]]]
let array1 = [ ["id":"1","products":["pid": 1, "name": "A", "price": "$5"]], ["id":"3","products":["pid": 3, "name": "B", "price": "$1"]]]
let array2 = [ ["id":"1","products":["pid": 1, "name": "A", "price": "$5"]], ["id":"3","products":["pid": 4, "name": "B", "price": "$1"]]]
let result = array2.filter{
let dict = $0
return !mainArry.contains{
return NSDictionary(dictionary: dict).isEqual(to: $0)
}
}
if result.isEmpty {
print("Same key values")
} else {
print("Diff key values")
}
Code review StackExchange站点是一个更好的地方,可以询问有关代码是否正常工作的问题。我强烈建议将字典解析为更强类型的结构或类,然后使这些对象符合Equatable。我无法在此处直接使用filter函数进行比较。
let mainArry = [ ["id":"1","products":["pid": 1, "name": "A", "price": "$5"]], ["id":"3","products":["pid": 3, "name": "B", "price": "$1"]], ["id":"2","products":["pid": 14, "name": "C", "price": "$15"]]]
let array1 = [ ["id":"1","products":["pid": 1, "name": "A", "price": "$5"]], ["id":"3","products":["pid": 3, "name": "B", "price": "$1"]]]
let array2 = [ ["id":"1","products":["pid": 1, "name": "A", "price": "$5"]], ["id":"3","products":["pid": 4, "name": "B", "price": "$1"]]]
let result = array2.filter{
let dict = $0
return !mainArry.contains{
return NSDictionary(dictionary: dict).isEqual(to: $0)
}
}
if result.isEmpty {
print("Same key values")
} else {
print("Diff key values")
}