Ios 错误：将Objective-C指针隐式转换为'；选择非空'；NSTimer选择器中的圆弧不允许

我有这样一种方法：

-(void)fastTapCartBack:(NSString*)ActionType

self.timer = [NSTimer scheduledTimerWithTimeInterval:1 target:self selector:[self performSelector:@selector(fastTapCartBack:) withObject:@"FAST"] userInfo:nil repeats:NO]

我想在NSTimer中将其用作选择器，如下所示：

-(void)fastTapCartBack:(NSString*)ActionType

self.timer = [NSTimer scheduledTimerWithTimeInterval:1 target:self selector:[self performSelector:@selector(fastTapCartBack:) withObject:@"FAST"] userInfo:nil repeats:NO]

但它有一个错误：

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ARC不允许将Objective-C指针隐式转换为“SEL\u Nonnull”

您正在传递一个方法调用

[self-performSelector:@selector（fastTapCartBack:）with Object:@“FAST”]

作为选择器，Objective-C不允许这样做

替换此

self.timer = [NSTimer scheduledTimerWithTimeInterval:1 target:self selector:[self performSelector:@selector(fastTapCartBack:) withObject:@"FAST"] userInfo:nil repeats:NO];

通过此

self.timer = [NSTimer scheduledTimerWithTimeInterval:1 target:self selector:[self performSelector:@selector(fastTapCartBack:) withObject:@"FAST"] userInfo:nil repeats:NO];

您应该使用NSInvocation方式

NSMethodSignature * signature = [ViewController instanceMethodSignatureForSelector:@selector(fastTapCartBack:)];
NSInvocation * invocation = [NSInvocation
             invocationWithMethodSignature:signature];
[invocation setTarget:self];
[invocation setSelector:@selector(fastTapCartBack:)];
NSString * argument = @"FAST";
[invocation setArgument:&argument atIndex:2];

self.timer2 = [NSTimer scheduledTimerWithTimeInterval:1 invocation:invocation repeats:NO];

---

不能在目标/操作模式中传递第二个参数

但是，对于

NSTimer

有一个非常合适的解决方案，

userInfo

参数

self.timer = [NSTimer scheduledTimerWithTimeInterval:1 
                                              target:self 
                                            selector:@selector(fastTapCartBack:)
                                            userInfo:@"FAST" 
                                             repeats:NO];

并在选择器方法中获取信息

-(void)fastTapCartBack:(NSTimer *)timer {
     NSString *info = (NSString *)timer.userInfo;
}

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是的，它是有效的，但我需要定义我方法的第二个参数。如何用指定的第二个参数定义我的选择器？@SaMiGiMiX你测试过我的答案吗？使用

NSInvocation

？是的，但在NSInvocation*调用上有错误和线程断点