Ios Openurl已刷新，无法打开

我有一个视图，里面有3个容器视图，其中两个是选择器，最后一个是2个按钮。其中一个按钮打开一个url，由两个选择器创建，另一个按钮刷新链接。 如果两个选择器都返回（null），则链接将工作。如果其中一个选择器返回一个值，并且单击了“刷新”按钮，则该链接将不再工作

    - (void)viewDidLoad
 {
[super viewDidLoad];
// Do any additional setup after loading the view.

[_button_amazon_link setTitle:@"amazon.de" forState:UIControlStateNormal];
[_button_ifixit_link setTitle:@"ifixit.com" forState:UIControlStateNormal];

[self refreshview];
}
- (void)didReceiveMemoryWarning
{
[super didReceiveMemoryWarning];
// Dispose of any resources that can be recreated.
}

-(void) refreshview{
AppDelegate *appdelegatestrings = (AppDelegate *) [[UIApplication sharedApplication] delegate];

appdelegatestrings.link_amazon = [NSString stringWithFormat:@"http://www.amazon.com/s/field-keywords=%@+%@", appdelegatestrings.model, appdelegatestrings.dead_thing];

appdelegatestrings.link_ifixit = [NSString stringWithFormat:@"http://www.ifixit.com/Device/%@/%@", appdelegatestrings.model, appdelegatestrings.dead_thing];
link_ifixit_ready = appdelegatestrings.link_ifixit;
link_amazon_ready = appdelegatestrings.link_amazon;

}
-(void) openurl : (NSString *)urlstring
{
NSLog(urlstring);
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:urlstring]];
}
- (IBAction)button_amazon_link_clicked:(id)sender {
[self openurl:link_amazon_ready];

}
- (IBAction)button_ifixit_link_clicked:(id)sender {
[self openurl:link_ifixit_ready];
}

- (IBAction)button_refresh:(id)sender {
[self refreshview];
}

---

这对我有用

当

[openurl://code>中的
urlstring
不起作用时，它的值是多少？链接：5/显示（例如，与选取器一致）链接是原始的（），但堆栈溢出删除。当我通过输出将这些链接复制到safari中时，链接起作用，但如果我单击了链接按钮，然后链接就不会打开，但只有在url没有空格的情况下才能打开。。。不管怎样
   -(IBAction)btn_press:(id)sender{
        [[UIApplication sharedApplication] openURL:[NSURL 
URLWithString:@"http://www.ifixit.com/Device/iPhone"]];
    }