NSpreditate针对iphone中的NSArray
如何使用NSpreditate针对iphone中的NSArray,iphone,search,nsarray,filtering,nspredicate,Iphone,Search,Nsarray,Filtering,Nspredicate,如何使用NSPredicate根据搜索查询筛选数组ivar中的值?我设法对字符串ivar使用NSPredicate。我有一个名为“user”的用户定义类,用于从AddressBook创建用户。这是我的密码 // User Defined Class named as "User" // In User.h @interface User : NSObject { NSString *firstName; NSString *lastName; NSString
NSPredicate
根据搜索查询筛选数组ivar中的值?我设法对字符串ivar使用NSPredicate
。我有一个名为“user”的用户定义类,用于从AddressBook创建用户。这是我的密码
// User Defined Class named as "User"
// In User.h
@interface User : NSObject {
NSString *firstName;
NSString *lastName;
NSString *company;
UIImage *userImage;
NSArray *phoneNumberArray;
NSArray *emailArray;
NSArray *urlArray;
NSArray *addressArray;
NSString *notes;
NSString *dateOfBirth;
}
// In SearchViewController.m
- (void)searchBar:(UISearchBar *)searchBar textDidChange:(NSString *)searchText{
// contactsArray is NSMutableArray
contactsArray = [Search searchContactsWithQuery:searchText];
NSLog(@"contactsArray count => %d",[contactsArray count]);
[contactsTableView reloadData];
}
// In Search.m
+(NSMutableArray*)searchContactsWithQuery:(NSString*)query {
NSLog(@"Query => %@",query);
NSMutableArray* predicates=[[NSMutableArray alloc] init];
// Create all predicates
NSPredicate * firstNamePredicate = [NSPredicate predicateWithFormat:@"firstName contains %@",query];
[predicates addObject:firstNamePredicate];
NSPredicate * lastNamePredicate = [NSPredicate predicateWithFormat:@"lastName contains %@",query];
[predicates addObject:lastNamePredicate];
NSPredicate * companyPredicate = [NSPredicate predicateWithFormat:@"company contains %@",query];
[predicates addObject:companyPredicate];
// Don't know how to use on array
// === START of ARRAY Predicate ====
NSPredicate *phoneNoPredicate = [NSPredicate predicateWithFormat:@"phoneNumberArray IN %@",query];
[predicates addObject:phoneNoPredicate];
NSPredicate *emailPredicate = [NSPredicate predicateWithFormat:@"emailArray contains %@",query];
[predicates addObject:emailPredicate];
NSPredicate *urlPredicate = [NSPredicate predicateWithFormat:@"urlArray contains %@",query];
[predicates addObject:urlPredicate];
NSPredicate *addressPredicate = [NSPredicate predicateWithFormat:@"addressArray contains %@",query];
// === END of ARRAY Predicate ====
NSPredicate *notesPredicate = [NSPredicate predicateWithFormat:@"notes contains %@",query];
[predicates addObject:notesPredicate];
NSPredicate *dobPredicate = [NSPredicate predicateWithFormat:@"dateOfBirth contains %@",query];
[predicates addObject:dobPredicate];
// Add predicates to array
NSPredicate *compoundPredicate = [NSCompoundPredicate orPredicateWithSubpredicates:predicates];
NSArray * filteredArray = [APP_DELEGATE.allUsersArray filteredArrayUsingPredicate:compoundPredicate];
return [NSMutableArray arrayWithArray:filteredArray];
}
使用phoneNumberArray、emailArray、urlArray和addressArray是因为用户可能有多个电话号码、电子邮件、地址、url条目,如家庭、工作、iPhone等
如何在数组上使用谓词?感谢您的任何帮助。谢谢您的方法是正确的,但是您需要使用字符串值创建谓词,而不是直接传递对象 您需要使用%k而不是%@像
[NSPredicate predicateWithFormat:@“firstName包含%k”,查询]代码>
请让我知道这是否有帮助。使用predicate:
是正确的方法。上面的代码是否不起作用?您确定数组中有与谓词匹配的值吗?数组中有与谓词匹配的值简化了谓词。不要使用复合谓词,而是尝试使用一个简单谓词过滤数组。实际上,您可以尝试将它们分别应用于9个单独的数组——这可能会为您提供问题所在的线索。