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NSpreditate针对iphone中的NSArray_Iphone_Search_Nsarray_Filtering_Nspredicate - Fatal编程技术网

NSpreditate针对iphone中的NSArray

NSpreditate针对iphone中的NSArray,iphone,search,nsarray,filtering,nspredicate,Iphone,Search,Nsarray,Filtering,Nspredicate,如何使用NSPredicate根据搜索查询筛选数组ivar中的值?我设法对字符串ivar使用NSPredicate。我有一个名为“user”的用户定义类,用于从AddressBook创建用户。这是我的密码 // User Defined Class named as "User" // In User.h @interface User : NSObject { NSString *firstName; NSString *lastName; NSString

如何使用
NSPredicate
根据搜索查询筛选数组ivar中的值?我设法对字符串ivar使用
NSPredicate
。我有一个名为“user”的用户定义类,用于从AddressBook创建用户。这是我的密码

  // User Defined Class named as "User"

// In User.h

@interface User : NSObject {

    NSString *firstName;
    NSString *lastName;
    NSString *company;
    UIImage *userImage;

    NSArray *phoneNumberArray;
    NSArray *emailArray;
    NSArray *urlArray;
    NSArray *addressArray;

    NSString *notes;
    NSString *dateOfBirth;
}

// In SearchViewController.m

- (void)searchBar:(UISearchBar *)searchBar textDidChange:(NSString *)searchText{

    //  contactsArray is NSMutableArray   
    contactsArray = [Search searchContactsWithQuery:searchText];
    NSLog(@"contactsArray count => %d",[contactsArray count]);
    [contactsTableView reloadData];
}

// In Search.m

+(NSMutableArray*)searchContactsWithQuery:(NSString*)query {

    NSLog(@"Query => %@",query);

    NSMutableArray*  predicates=[[NSMutableArray alloc] init];

    // Create all predicates
    NSPredicate * firstNamePredicate = [NSPredicate predicateWithFormat:@"firstName contains %@",query];
    [predicates addObject:firstNamePredicate];
    NSPredicate * lastNamePredicate = [NSPredicate predicateWithFormat:@"lastName contains %@",query];
    [predicates addObject:lastNamePredicate];
    NSPredicate * companyPredicate = [NSPredicate predicateWithFormat:@"company contains %@",query];
    [predicates addObject:companyPredicate];

    // Don't know how to use on array
    // === START of ARRAY Predicate ====

NSPredicate *phoneNoPredicate = [NSPredicate predicateWithFormat:@"phoneNumberArray IN %@",query];
    [predicates addObject:phoneNoPredicate];

    NSPredicate *emailPredicate = [NSPredicate predicateWithFormat:@"emailArray contains %@",query];
    [predicates addObject:emailPredicate];
    NSPredicate *urlPredicate = [NSPredicate predicateWithFormat:@"urlArray contains %@",query];
    [predicates addObject:urlPredicate];

    NSPredicate *addressPredicate = [NSPredicate predicateWithFormat:@"addressArray contains %@",query];

    // === END of ARRAY Predicate ====

    NSPredicate *notesPredicate = [NSPredicate predicateWithFormat:@"notes contains %@",query];
    [predicates addObject:notesPredicate];
    NSPredicate *dobPredicate = [NSPredicate predicateWithFormat:@"dateOfBirth contains %@",query];
    [predicates addObject:dobPredicate]; 

    // Add predicates to array
    NSPredicate *compoundPredicate = [NSCompoundPredicate orPredicateWithSubpredicates:predicates];

    NSArray * filteredArray = [APP_DELEGATE.allUsersArray filteredArrayUsingPredicate:compoundPredicate];

    return [NSMutableArray arrayWithArray:filteredArray];

} 
使用phoneNumberArray、emailArray、urlArray和addressArray是因为用户可能有多个电话号码、电子邮件、地址、url条目,如家庭、工作、iPhone等


如何在数组上使用谓词?感谢您的任何帮助。谢谢

您的方法是正确的,但是您需要使用字符串值创建谓词,而不是直接传递对象

您需要使用%k而不是%@像

[NSPredicate predicateWithFormat:@“firstName包含%k”,查询]


请让我知道这是否有帮助。

使用predicate:
是正确的方法。上面的代码是否不起作用?您确定数组中有与谓词匹配的值吗?数组中有与谓词匹配的值简化了谓词。不要使用复合谓词,而是尝试使用一个简单谓词过滤数组。实际上,您可以尝试将它们分别应用于9个单独的数组——这可能会为您提供问题所在的线索。