当应用程序终止并再次启动时，无法插入iphone的sqlite数据库

该应用程序第一次工作正常，但当我重新启动它时，它可以读取早期的值，但无法插入新值。。。请帮忙

以下是我如何称呼这个

-(void)checkAndCreateDatabase{
    NSLog(@"hello");
    databaseName = @"EMAP234.sql";
    NSArray *documentPaths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES);
    NSString *documentsDir = [documentPaths objectAtIndex:0];
    databasePath = [documentsDir stringByAppendingPathComponent:databaseName];
    NSLog(@"database path %@",databasePath);
    BOOL success;

    // Create a FileManager object, we will use this to check the status
    // of the database and to copy it over if required
    NSFileManager *fileManager = [NSFileManager defaultManager];

    // Check if the database has already been created in the users filesystem
    success = [fileManager fileExistsAtPath:databasePath];

    // If the database already exists then return without doing anything
    if(success) return;

    // If not then proceed to copy the database from the application to the users filesystem

    // Get the path to the database in the application package
    NSString *databasePathFromApp = [[[NSBundle mainBundle] resourcePath] stringByAppendingPathComponent:databaseName];

    // Copy the database from the package to the users filesystem
    [fileManager copyItemAtPath:databasePathFromApp toPath:databasePath error:nil];
    [fileManager release];
}

-(void)insertIntoDatabase:(NSString *)insertCommand{
    // Setup the database object
    sqlite3 *database;

    // Open the database from the users filessytem
    if(sqlite3_open([databasePath UTF8String], &database) == SQLITE_OK) {

        // Setup the SQL Statement and compile it for faster access
        const char *sqlStatement = [insertCommand UTF8String];
        sqlite3_stmt *compiledStatement;


        if(sqlite3_prepare_v2(database, sqlStatement, -1, &compiledStatement, NULL) == SQLITE_OK) {
            // Loop through the results and add them to the feeds array
            NSLog(@"inserted");
            while(sqlite3_step(compiledStatement) == SQLITE_ROW) {}
        }

        // Release the compiled statement from memory
        sqlite3_finalize(compiledStatement);

    }
    sqlite3_close(database);

}

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你好Ankit我用了你的密码打了电话

DatabaseOperations *obj=[[DatabaseOperations alloc]init];
[obj checkAndCreateDatabase];
NSLog(@"patient ID %d",[obj readMaxPatientIDFromDatabase]);

patientID= [NSString stringWithFormat:@"HCI%d", ([obj readMaxPatientIDFromDatabase]+1)];
NSLog(@"patient ID %@",patientID);
[self generatePatientInsertCommand];
[obj insertIntoDatabase:patientInsertCommand];
[self generateCarrierInsertCommand];
[obj insertIntoDatabase:carrierInsertCommand];
[self generateSyncTableInsertCommand];
[obj insertIntoDatabase:syncTableInsertCommand];
NSString *msg=@"your PatientID is";
[obj release];
msg=[msg stringByAppendingString:patientID];
UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"REGISTERED" message:msg delegate:self cancelButtonTitle:@"ok" otherButtonTitles: nil];
[alert show];
[alert release];

我唯一改变的是使用不同的数据库文件，我在checkAndCreateDatabase函数中选择了这个文件

[self checkAndCreateDatabase];
[self insertIntoDatabase:[NSString stringWithFormat:@"INSERT INTO User (uId,userName,userBirthday) VALUES (\"%d\", \"%@\", \"%@\" )",3,@"Admin",@"2010-12-01"]];

---

代码在每次插入新uId时都运行良好。请检查您的读取函数，如果可能，请将读取函数的代码与上述代码以及调用这两个函数的方式（即读取和插入函数）一起粘贴。

数据库中没有条目，我已通过sqlite管理器进行了检查。我在nsobject类中有这两个函数，并从rootViewController调用它们。您第一次提到应用程序工作正常，但当我重新启动它时，它可以读取早期值，但无法插入新值。你能用从rootviewController调用这些方法的方式粘贴代码吗？通过在创建数据库时创建模式而不是动态创建表来解决问题。

-(void)checkAndCreateDatabase{
    NSLog(@"hello");
    databaseName = @"MasterDB.sqlite";
....
}