如何在两个数字之间列出数字java spark datafrme

数据帧输入：

请求数据帧输出

如果输入文件有冒号，我们需要找到一个冒号 前任： 1:10->1,2,3,4,5,6,7,8,9,10

这可能与正则表达式有关。我不清楚，请找人帮忙

UDF:
def myudf2=(input:String)=>{
    val regex = "('\\d+':'\\d+')".r
    val out = new ListBuffer[String]()
    input.replaceAll("'", "").split(",").map(x=>{
      if(x.matches("(\\d+:\\d+)")){
        val colon = x.split(":")
        out += (colon(0).toInt to colon(1).toInt).mkString(", ")
      } else {
        out += x
      } 
    })
    out.mkString(",").replaceAll("\\[|\\]", "")
  }

val df = Seq((1,"'1':'5','6','7':'10'"),(2,"'1':'6','7','8':'12'")).toDF("id","number")
scala> df.show
+---+--------------------+
| id|              number|
+---+--------------------+
|  1|'1':'5','6','7':'10'|
|  2|'1':'6','7','8':'12'|
+---+--------------------+
val myCostumeudf = udf(myudf2)
scala> val outDF = df.withColumn("output", myCostumeudf(df("number")))
scala> outDF.show(5,false)
+---+--------------------+---------------------------------------+
|id |number              |output                                 |
+---+--------------------+---------------------------------------+
|1  |'1':'5','6','7':'10'|1, 2, 3, 4, 5, 6, 7, 8, 9, 10          |
|2  |'1':'6','7','8':'12'|1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12  |
+---+--------------------+---------------------------------------+

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请尝试上述操作。

请提供您已经尝试过的一些代码，否则您的问题将不会得到任何答案/帮助