Java Android:从网站读取HTML并将其发布到屏幕上
我的目标是创建一个非常基本的应用程序,它读取HTML并将其存储到字符串中。我只对网站来源的一行内容感兴趣。我发现了一个主题,它表明:Java Android:从网站读取HTML并将其发布到屏幕上,java,android,html,parsing,sdk,Java,Android,Html,Parsing,Sdk,我的目标是创建一个非常基本的应用程序,它读取HTML并将其存储到字符串中。我只对网站来源的一行内容感兴趣。我发现了一个主题,它表明: String bodyHtml = "null"; try { String myUri = "http://www.spring8.or.jp/ext/ja/status/text.html"; HttpClient httpClient = new DefaultHttpC
String bodyHtml = "null";
try {
String myUri = "http://www.spring8.or.jp/ext/ja/status/text.html";
HttpClient httpClient = new DefaultHttpClient();
HttpGet get = new HttpGet(myUri);
HttpResponse response = httpClient.execute(get);
// Build up result
bodyHtml = EntityUtils.toString(response.getEntity());
} catch (Exception e) {
}
url.setText(bodyHtml);
url是我的文本视图。据我所知,我已在清单中正确设置了权限
但是,当我在手机和模拟器上运行此代码时,它似乎根本不起作用。我什么也得不到。我错过什么了吗
谢谢你试试这个而不是实体工具
BufferedReader rd = new BufferedReader(new InputStreamReader(
response.getEntity().getContent()));
String line = "";
String newLine = "";
while ((line = rd.readLine()) != null) {
newLine = newLine.concat(line);
}
System.out.println(newLine);
在的execute方法中,也放置一个,如下所示:
HttpContext localContext = new BasicHttpContext();
HttpResponse response = httpClient.execute(get, localContext);
并使用:
如果它不起作用,你的互联网连接可能会有问题。
顺便说一句,别忘了android.permission.INTERNET权限 试试这个
调用下面的方法下载HTml内容并在参数中传递Url
private void downloadText(String urlStr) {
progressDialog = ProgressDialog.show(this, "",
"Download Text from " + urlStr);
final String url = urlStr;
new Thread () {
public void run() {
int BUFFER_SIZE = 2000;
InputStream in = null;
Message msg = Message.obtain();
msg.what=1;
try {
in = openHttpConnection(url);
InputStreamReader isr = new InputStreamReader(in);
int charRead;
text = "";
char[] inputBuffer = new char[BUFFER_SIZE];
while ((charRead = isr.read(inputBuffer))>0)
{
String readString =
String.copyValueOf(inputBuffer, 0, charRead);
text += readString;
inputBuffer = new char[BUFFER_SIZE];
}
Bundle b = new Bundle();
b.putString("text", text);
msg.setData(b);
in.close();
}catch (IOException e2) {
e2.printStackTrace();
}
messageHandler.sendMessage(msg);
}
}.start();
}
这是返回InputStream对象的帮助器方法
private InputStream openHttpConnection(String urlStr) {
InputStream in = null;
int resCode = -1;
try {
URL url = new URL(urlStr);
URLConnection urlConn = url.openConnection();
if (!(urlConn instanceof HttpURLConnection)) {
throw new IOException ("URL is not an Http URL");
}
HttpURLConnection httpConn = (HttpURLConnection)urlConn;
httpConn.setAllowUserInteraction(false);
httpConn.setInstanceFollowRedirects(true);
httpConn.setRequestMethod("GET");
httpConn.connect();
resCode = httpConn.getResponseCode();
if (resCode == HttpURLConnection.HTTP_OK) {
in = httpConn.getInputStream();
}
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return in;
}
现在使用Handler在textView中显示字符串
private Handler messageHandler = new Handler() {
public void handleMessage(Message msg) {
super.handleMessage(msg);
switch (msg.what) {
case 1:
TextView text = (TextView) findViewById(R.id.textview01);
text.setText(msg.getData().getString("text"));
break;
}
progressDialog.dismiss();
}
};
在清单中提供互联网权限 你在logcat中有什么错误吗?您是否已将此权限添加到AndroidMainfest.xml中?非常感谢各位的回复。我已经在模拟器上尝试过了,它确实有效。然而,它似乎对我的物理星系S2不起作用,即使它连接到互联网。有没有办法解决这个问题?到底发生了什么?整个应用程序突然崩溃,或者你得到的只是一个空的文本视图?不,应用程序没有崩溃。我没有像emulator那样获取HTML源代码,而是获取在尝试检索HTML源代码之前分配的空值。您是否已将INTERNET权限添加到清单中。如果有,请删除它,然后使用Android清单编辑器再次添加。我肯定已经这样做了,它不在应用程序部分。我真的不知道是什么原因导致了这种情况:(非常感谢,它在我的模拟器中工作。我在第一个响应中添加了一个问题。非常感谢,它在我的模拟器中工作。我在第一个响应中添加了一个问题。
private Handler messageHandler = new Handler() {
public void handleMessage(Message msg) {
super.handleMessage(msg);
switch (msg.what) {
case 1:
TextView text = (TextView) findViewById(R.id.textview01);
text.setText(msg.getData().getString("text"));
break;
}
progressDialog.dismiss();
}
};