用java编写20-99到单词之间的数字

我是一名java初学者，我们被要求创建一个程序，读取20到99之间的整数，并将数字写成单词。如果数字大于99或小于20，程序将报告超出范围的错误。当用户键入-1时，程序停止

到目前为止，我有这个代码，我不确定是否没有什么问题：

导入java.util.Scanner； 公开课问题1{ 公共静态void numberToWordint num，字符串val{ String ON[]= {，一，二，三，四，五，六，七，八，九，十，十一，十二，十三，十四，十四，η，y，y，y }; 字符串十[]={，二十，三十，四十，五十，六十，七十，八十，九十}； 如果num>19{ System.out.printtens[num/10]++one[num%10]； }否则{ System.out.printones[num]； } 如果num>0{ System.out.printlnval； } } 公共静态无效字符串[]args{ 整数=0； Scanner Scanner=新ScannerSystem.in； System.out.Print请键入一个介于20和99之间的数字，或在结尾处键入-1:； 编号=scanner.nextInt； whilenumber！=-1{

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如果number>=20&&number您的代码正常工作，那么word FOURTY中只有一个小的输入错误，应该是四十。我还将从数组1和tens中的字符串中删除不必要的空格。您可以在此处插入一个空格：

System.out.print(tens[num / 10] + " " + ones[num % 10]);

因此，数组中的空格字符是冗余的

String ones[] = {
    "", "ONE", "TWO", "THREE", " FOUR", "FIVE", "SIX", "SEVEN", "EIGHT", "NINE", "TEN",
    "ELEVEN", "TWELVE", " THIRTEEN", "FOURTEEN", "FIFTEEN", "SIXTEEN", "SEVENTEEN", "EIGHTEEN", "NINETEEN"
};
String tens[] = {
    " ", " ", "TWENTY", "THIRTY", "FORTY", "FIFTY", "SIXTY", "SEVENTY", "EIGHTY", "NINETY"
};

编辑：如果我在做作业，我可能会这样写程序：

import java.util.Scanner;

public class Question1 {

    private static String ones[] = {
            "", "ONE", "TWO", "THREE", " FOUR", "FIVE", "SIX", "SEVEN", "EIGHT", "NINE", "TEN",
            "ELEVEN", "TWELVE", " THIRTEEN", "FOURTEEN", "FIFTEEN", "SIXTEEN", "SEVENTEEN", "EIGHTEEN", "NINETEEN"
    };

    private static String tens[] = {
            " ", " ", "TWENTY", "THIRTY", "FORTY", "FIFTY", "SIXTY", "SEVENTY", "EIGHTY", "NINETY"
    };

    public static void numberToWord(int num, String val) {
        if (num > 19)
            System.out.print(tens[num / 10] + " " + ones[num % 10]);
        else
            System.out.print(ones[num]);

        if (num > 0)
            System.out.println(val);
    }

    public static void main(String[] args) {
        int number;
        Scanner scanner = new Scanner(System.in);

        while (true) {
            System.out.print("\nPlease type a number between 20 and 99 OR type -1 to end: ");
            number = scanner.nextInt();

            if (number == -1)
                break; // Leave the loop

            if (number >= 20 && number <= 99)
                numberToWord(number, " ");
            else
                System.out.print("Out of bounds. Try Again");
        }
    }

}

但是与您的解决方案相比，代码风格只有一些微小的改进

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祝您学习Java好运！：

如果它运行时没有错误-您的代码很好。有任何Java错误吗？这与javascript无关。此外，您怎么能不知道是否没有错误？您是否尝试过实际运行代码？