Java 无法从布局中删除视图
我正在创建一个小应用程序,您可以通过单击按钮来添加或删除表行。每当我单击“添加行”按钮时,该按钮都会向布局中添加一个表行,并执行它应该执行的操作。然而,“delete line”并没有删除新添加的表行,而是像预期的那样递减(int count)。我已经在上面搜索了大约4到5个小时,现在我没有运气了。代码如下:Java 无法从布局中删除视图,java,android,layout,view,Java,Android,Layout,View,我正在创建一个小应用程序,您可以通过单击按钮来添加或删除表行。每当我单击“添加行”按钮时,该按钮都会向布局中添加一个表行,并执行它应该执行的操作。然而,“delete line”并没有删除新添加的表行,而是像预期的那样递减(int count)。我已经在上面搜索了大约4到5个小时,现在我没有运气了。代码如下: int count = 0; public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInst
int count = 0;
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
Button buttonAdd = (Button) findViewById(R.id.button1);
Button buttonDel = (Button) findViewById(R.id.button2);
buttonAdd.setOnClickListener(this);
buttonDel.setOnClickListener(this);
}
public void onClick(View v) {
TableLayout tableLayout1;
EditText editText1;
EditText editText2;
TableRow tempRow;
EditText tempText1;
EditText tempText2;
TableRow tableRow1;
tableLayout1 = (TableLayout) findViewById(R.id.tableLayout1);
editText1 = (EditText) findViewById(R.id.editText1);
editText2 = (EditText) findViewById(R.id.editText2);
tempRow = new TableRow(MainActivity.this);
tempText1 = new EditText(MainActivity.this);
tempText2 = new EditText(MainActivity.this);
tempText1.setInputType(InputType.TYPE_CLASS_TEXT);
tempText2.setInputType(InputType.TYPE_NUMBER_FLAG_DECIMAL);
tableRow1 = (TableRow) findViewById(R.id.tableRow1);
tempRow.setLayoutParams(new LayoutParams(LayoutParams.FILL_PARENT, LayoutParams.WRAP_CONTENT));
tempText1.setLayoutParams(editText1.getLayoutParams());
tempText2.setLayoutParams(editText2.getLayoutParams());
switch(v.getId()){
case R.id.button1:
if(count != 9){
count++;
tempRow.addView(tempText1);
tempRow.addView(tempText2);
tableLayout1.addView(tempRow);
} else {
final AlertDialog alertDialog = new AlertDialog.Builder(MainActivity.this).create(); //Read Update
alertDialog.setTitle("Error");
alertDialog.setMessage("You can only have 10 rows!");
alertDialog.setButton("Ok", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
alertDialog.dismiss();
}
});
alertDialog.show();
}
break;
case R.id.button2:
if(count != 0){
count--;
tempRow.removeView(tempText1);
tempRow.removeView(tempText2);
tableLayout1.removeView(tempRow);
//tableLayout1.invalidate();
} else {
final AlertDialog alertDialog = new AlertDialog.Builder(MainActivity.this).create(); //Read Update
alertDialog.setTitle("Error");
alertDialog.setMessage("You must have at least one row!");
alertDialog.setButton("Ok", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
alertDialog.dismiss();
}
});
alertDialog.show();
}
break;
default:
//Do something;
}
}
每次执行onClick时,代码都会生成一个新的
TableRow
。仅当要添加行时才应执行此操作。如果要删除一行,则必须使用findViewById(id)
在现有视图中查找要删除的行,然后在该对象上运行removeView
case R.id.button2:
if ( count != 0 ) {
count--;
tempRow = (TableRow)findViewById( idoftablerowtodelete );
tableLayout1.removeView( tempRow );
这意味着您必须在创建表行时,使用
setId
,在每个表行上设置一个id,并对其进行跟踪。这是一个组织问题,请尝试以下方法:
public void onClick(View v) {
// These should be class variables, like count, you don't need to re-find it on every click
TableLayout tableLayout1 = (TableLayout) findViewById(R.id.tableLayout1);
EditText editText1 = (EditText) findViewById(R.id.editText1);
EditText editText2 = (EditText) findViewById(R.id.editText2);
switch(v.getId()){
case R.id.button1:
if(count != 9){
count++;
// Create the row only when the add button is clicked
TableRow tempRow = new TableRow(MainActivity.this);
EditText tempText1 = new EditText(MainActivity.this);
EditText tempText2 = new EditText(MainActivity.this);
tempText1.setInputType(InputType.TYPE_CLASS_TEXT);
tempText2.setInputType(InputType.TYPE_NUMBER_FLAG_DECIMAL);
tempRow.setLayoutParams(new LayoutParams(LayoutParams.FILL_PARENT, LayoutParams.WRAP_CONTENT));
tempText1.setLayoutParams(editText1.getLayoutParams());
tempText2.setLayoutParams(editText2.getLayoutParams());
tempRow.addView(tempText1);
tempRow.addView(tempText2);
tableLayout1.addView(tempRow);
} else {
// Consider using Activity's showDialog() method, to reuse this "error" dialog rather than create a new one every time
final AlertDialog alertDialog = new AlertDialog.Builder(MainActivity.this).create(); //Read Update
alertDialog.setTitle("Error");
alertDialog.setMessage("You can only have 10 rows!");
alertDialog.setButton("Ok", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
alertDialog.dismiss();
}
});
alertDialog.show();
}
break;
case R.id.button2:
if(count != 0){
// Remove the last row at count or use "tableLayout1.getChildCount() - 1"
tableLayout1.removeView(tableLayout1.getChildAt(count));
count--;
} else {
// Consider reusing the other "error" Dialog and simply changing the message
final AlertDialog alertDialog = new AlertDialog.Builder(MainActivity.this).create(); //Read Update
alertDialog.setTitle("Error");
alertDialog.setMessage("You must have at least one row!");
alertDialog.setButton("Ok", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
alertDialog.dismiss();
}
});
alertDialog.show();
}
break;
default:
//Do something;
}
}
您的删除代码是“删除”临时视图(例如tentext1
),它们实际上不在表中-它们是在onClick
方法中动态创建的。不要在进入onClick
时立即实例化所有这些对象,而是在每个switch语句的主体中进行实例化。对于“添加”按钮,只需复制并粘贴即可。对于删除行,将对象设置为要删除的行
您似乎没有办法选择要删除的行,但假设您在其他地方这样做,您可以使用
TableLayout.removeViewAt(int index)
选择哪一行。还有TableLayout.removeView(视图视图)
如果你有视图本身而不是索引。先生,你是个天才。非常感谢。我现在唯一的问题是,在我添加一行之后,删除该行,然后再次尝试添加一行,我在第57行收到一个NullPointerException。它将异常指向“testext1.setLayoutParams(editText1.getLayoutParams());”这很奇怪,是否可以将所有LogCat错误编辑到您的问题中?所以我可以看到发生了什么。
public void onClick(View v) {
// These should be class variables, like count, you don't need to re-find it on every click
TableLayout tableLayout1 = (TableLayout) findViewById(R.id.tableLayout1);
EditText editText1 = (EditText) findViewById(R.id.editText1);
EditText editText2 = (EditText) findViewById(R.id.editText2);
switch(v.getId()){
case R.id.button1:
if(count != 9){
count++;
// Create the row only when the add button is clicked
TableRow tempRow = new TableRow(MainActivity.this);
EditText tempText1 = new EditText(MainActivity.this);
EditText tempText2 = new EditText(MainActivity.this);
tempText1.setInputType(InputType.TYPE_CLASS_TEXT);
tempText2.setInputType(InputType.TYPE_NUMBER_FLAG_DECIMAL);
tempRow.setLayoutParams(new LayoutParams(LayoutParams.FILL_PARENT, LayoutParams.WRAP_CONTENT));
tempText1.setLayoutParams(editText1.getLayoutParams());
tempText2.setLayoutParams(editText2.getLayoutParams());
tempRow.addView(tempText1);
tempRow.addView(tempText2);
tableLayout1.addView(tempRow);
} else {
// Consider using Activity's showDialog() method, to reuse this "error" dialog rather than create a new one every time
final AlertDialog alertDialog = new AlertDialog.Builder(MainActivity.this).create(); //Read Update
alertDialog.setTitle("Error");
alertDialog.setMessage("You can only have 10 rows!");
alertDialog.setButton("Ok", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
alertDialog.dismiss();
}
});
alertDialog.show();
}
break;
case R.id.button2:
if(count != 0){
// Remove the last row at count or use "tableLayout1.getChildCount() - 1"
tableLayout1.removeView(tableLayout1.getChildAt(count));
count--;
} else {
// Consider reusing the other "error" Dialog and simply changing the message
final AlertDialog alertDialog = new AlertDialog.Builder(MainActivity.this).create(); //Read Update
alertDialog.setTitle("Error");
alertDialog.setMessage("You must have at least one row!");
alertDialog.setButton("Ok", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int which) {
alertDialog.dismiss();
}
});
alertDialog.show();
}
break;
default:
//Do something;
}
}