Java 为什么在写入字节数组时ObjectOutputStream.writeObject比写入字节快?
我做了一个小的基准测试,发现Java 为什么在写入字节数组时ObjectOutputStream.writeObject比写入字节快?,java,objectoutputstream,Java,Objectoutputstream,我做了一个小的基准测试,发现ObjectOutputStream.writeObject比ObjectOutputStream.write(byte[]bytes)快,但我似乎找不到可能的解释,因为在幕后,writeObject将间接调用ObjectOutputStream.write(byte[]bytes) 测试代码 publicstaticvoidmain(字符串[]args)引发异常{ 字节[]字节=新字节[10000]; 对于(int i=0;i
ObjectOutputStream.writeObject
比ObjectOutputStream.write(byte[]bytes)
快,但我似乎找不到可能的解释,因为在幕后,writeObject
将间接调用ObjectOutputStream.write(byte[]bytes)
测试代码
publicstaticvoidmain(字符串[]args)引发异常{
字节[]字节=新字节[10000];
对于(int i=0;i<10000;++i){
字节[i]=(字节)(i%256);
}
ByteArrayOutputStream out2=新建ByteArrayOutputStream();
try(ObjectOutputStream ostream2=新的ObjectOutputStream(out2)){
对于(int i=0;i<10000;++i){
ostream2.writeInt(字节.长度);
ostream2.write(字节,0,字节.长度);
}
out2.reset();
长启动=System.nanoTime();
对于(int i=0;i<10000;++i){
ostream2.writeInt(字节.长度);
ostream2.write(字节,0,字节.长度);
}
long end=System.nanoTime();
System.out.println(“write byte[]take:”+((end-start)/1000)+“micros”);
}
ByteArrayOutputStream out=新建ByteArrayOutputStream();
try(ObjectOutputStream ostream=newobjectoutputstream(out)){
对于(int i=0;i<10000;++i){
ostream.writeObject(字节);
}
out.reset();
长启动=System.nanoTime();
对于(int i=0;i<10000;++i){
ostream.writeObject(字节);
}
long end=System.nanoTime();
System.out.println(“writeObject take:”+((结束-开始)/1000)+“micros”);
}
}
输出
写入字节[]花费:15445微秒
写入对象:3111微秒
ObjectOutputStream.writeObject()
保存写入的对象。如果您已经编写了该对象,它将只向同一对象写入句柄,而不是整个对象。我对您的代码做了一些修改:
public class Test {
public static final int REPS = 10000;
public static void main(String argv[]) throws IOException {
ByteArrayOutputStream out2 = new ByteArrayOutputStream();
try (ObjectOutputStream ostream2 = new ObjectOutputStream(out2)) {
writeBytes(ostream2);
out2.reset();
long start = System.nanoTime();
writeBytes(ostream2);
long end = System.nanoTime();
System.out.println("write byte[] took: " + ((end - start) / 1000) + " micros");
}
ByteArrayOutputStream out = new ByteArrayOutputStream();
try (ObjectOutputStream ostream = new ObjectOutputStream(out)) {
writeObject(ostream);
out.reset();
long start = System.nanoTime();
writeObject(ostream);
long end = System.nanoTime();
System.out.println("writeObject took: " + ((end - start) / 1000) + " micros");
}
}
private static void writeObject(ObjectOutputStream ostream) throws IOException {
for (int i = 0; i < REPS; ++i) {
final byte[] bytes = bytes();
ostream.writeObject(bytes);
}
}
private static void writeBytes(ObjectOutputStream ostream2) throws IOException {
for (int i = 0; i < REPS; ++i) {
final byte[] bytes = bytes();
ostream2.writeInt(bytes.length);
ostream2.write(bytes, 0, bytes.length);
}
}
static byte[] bytes() {
byte[] bytes = new byte[REPS];
for (int i = 0; i < REPS; ++i) {
bytes[i] = (byte) i;
}
return bytes;
}
}
事实上,你是对的。我每次都会替换代码以拥有一个新的数组,写入字节数组现在比writeObject快。我完全忘记了WriteObject所做的缓存。谢谢你的回答。事实上,我完全忘记了writeObject中的缓存机制
public class Test {
public static final int REPS = 10000;
public static void main(String argv[]) throws IOException {
ByteArrayOutputStream out2 = new ByteArrayOutputStream();
try (ObjectOutputStream ostream2 = new ObjectOutputStream(out2)) {
writeBytes(ostream2);
out2.reset();
long start = System.nanoTime();
writeBytes(ostream2);
long end = System.nanoTime();
System.out.println("write byte[] took: " + ((end - start) / 1000) + " micros");
}
ByteArrayOutputStream out = new ByteArrayOutputStream();
try (ObjectOutputStream ostream = new ObjectOutputStream(out)) {
writeObject(ostream);
out.reset();
long start = System.nanoTime();
writeObject(ostream);
long end = System.nanoTime();
System.out.println("writeObject took: " + ((end - start) / 1000) + " micros");
}
}
private static void writeObject(ObjectOutputStream ostream) throws IOException {
for (int i = 0; i < REPS; ++i) {
final byte[] bytes = bytes();
ostream.writeObject(bytes);
}
}
private static void writeBytes(ObjectOutputStream ostream2) throws IOException {
for (int i = 0; i < REPS; ++i) {
final byte[] bytes = bytes();
ostream2.writeInt(bytes.length);
ostream2.write(bytes, 0, bytes.length);
}
}
static byte[] bytes() {
byte[] bytes = new byte[REPS];
for (int i = 0; i < REPS; ++i) {
bytes[i] = (byte) i;
}
return bytes;
}
}
write byte[] took: 51697 micros
writeObject took: 57203 micros