Java 猜游戏错误（主要是扫描器）

编辑1-我将所有sc.nextInt更改为Integer.parseInt（sc.nextLine（）），现在我有一些错误，但更少

编辑2-它现在运行，但我得到东西打印2倍，游戏没有结束在第10轮结束，我错过了一个总胜利线在结束。我认为错误发生在获胜之后

编辑3-2倍冷/热打印固定。修复了2x标题（在wins方法中重复左行）。新的（希望是最后一个错误）-第一轮游戏只允许3次尝试，其他轮4次。样本运行：

I will choose a number between 1 and 10
You have 3 tries to get it right

Round 1

Enter a new guess: 5
Cold
5
Cold
5
You lose!
You have won 0 out of 1 rounds.

Round 2

Enter a new guess: 5
Cold
5
Cold
5
Cold
5
You lose!
You have won 0 out of 2 rounds.

Round 3

Enter a new guess: 5
Cold
5
Cold
5
Cold
5
You lose!
You have won 0 out of 3 rounds.

第1类：

import java.util.Scanner;

public class GuessRunner 
{   
public static void main(String[] args) 
{
    Scanner sc = new Scanner(System.in);

    System.out.print("I will choose a number between 1 and 10" + 
                    '\n' + "You have 3 tries to get it right" + '\n');

    GuessCalc game = new GuessCalc();
    while (game.getRounds() <= 10)
    {   
        System.out.println('\n' + "Round " + game.getRounds() + '\n');
        System.out.print("Enter a new guess: ");
        int guess = Integer.parseInt(sc.nextLine());

        do
        {
            game.rounds(guess);
            guess = Integer.parseInt(sc.nextLine());
        } 
        while (game.roundOver == false);

        System.out.println(game.wins());
    }

    sc.close();
}
}

---

扫描仪的问题是，扫描仪非常非常奇怪。我已经用了好几年了，她讨厌我只把她用在快速和肮脏的输入上。我甚至不想开始描述发生的奇怪的事情，但解释通常围绕着非-nextLine（）方法如何处理换行符（无论它们是否使用/忽略它们）

我对scanner的建议是只使用它的hasNextLine（）和nextLine（）方法。它们是我发现的唯一方法，因为使用它们的每个人都可以预测方法的行为。然后，您可以检查它是一个数字（匹配（“[1-9]+[0-9]*”），还是仅为野生型，直接执行Integer.parseInt（）

看见 游戏=新的猜测计算（猜测）； 是一个循环在类1中看起来很奇怪。这看起来像是一个错误，因为轮次将不断重置

编辑1：

如果您的代码不希望在每一轮重置随机数并在每一轮重置“尝试”计数（代码在每一轮都丢弃当前游戏），以下代码可能会帮助您：

import java.util.Scanner;

public class GuessRunner {
    public static void main(String[] args) throws InterruptedException {

        System.out.print("I will choose a number between 1 and 10" + '\n'
            + "You have 3 tries to get it right" + '\n');

        GuessCalc game = new GuessCalc();
        while (game.getRounds() <= 10) {

            game.playRound();
            System.out.println(game.wins());

        }

}
}

您的代码格式不正确（无法编译），我不100%知道您的意图（例如，如果要在10轮中获得尽可能多的正确随机数，或者他们在10轮中有3次猜测，则未知）。祝你好运。

尝试添加

---

sc.nextLine（）在
sc.nextInt（）之后哪个将使用新行字符
可以从我的第二个类获取输入吗？我可以在那里创建另一个方法来处理新的轮次，但我试图在我的客户机类（1）中保留所有输入@LazerWing，你可以，只是不像你的代码现在这样。在第二个类中，您使用的是nextInt，这就是导致新错误的原因。我将编辑我的答案。我的想法是每轮3次尝试，10轮，每轮都有一个新的数字。makeGuess方法的布尔返回的目的是什么我不认为它是正确的used@LazerWing如果是每个随机数三次尝试，则希望类在循环中循环。“makeGuess方法上的布尔返回的目的是什么？我看不到它被使用了”与之前返回的字符串的目的相同。
import java.util.Scanner;

public class GuessRunner {
    public static void main(String[] args) throws InterruptedException {

        System.out.print("I will choose a number between 1 and 10" + '\n'
            + "You have 3 tries to get it right" + '\n');

        GuessCalc game = new GuessCalc();
        while (game.getRounds() <= 10) {

            game.playRound();
            System.out.println(game.wins());

        }

}
}

import java.util.Scanner;

public class GuessCalc {
    private int wins, rounds = 0, num = (int) (1 + Math.random() * 10);
    private int tries = 0;
    private Scanner sc=new Scanner(System.in);

    /**
    * Constructs the game
    * 
    * @param guess
    *            the player's guess
    */
    public GuessCalc() {

    }

    /**
    * Runs the rounds and determines if they win
    * 
    * @return outcome if they won (true) or lost (false);
    */
    public boolean playRound() {
        startNewRound();
        System.out.printf("Round %d \n\n", this.getRounds());

        while(true){
            System.out.println("Enter a new guess: ");

            int guess = Integer.parseInt(sc.nextLine());

            printHotOrCold(guess);

            if (guess == num) {
                wins++;

                System.out.println("Jackpot! Setting a new random number");

                return true;
            }else if(tries==3){
                System.out.println("Oops, didn't succeed. Better luck next time. The number was "+num);

                return false;//ran out of tries
            }else{
                //got it wrong but still has guesses left
            }
        }

    }

    public final void startNewRound() {
         rounds++;
         tries = 0;
         num = (int) (1 + Math.random() * 10);// set a new random number    

    }

    /**
    * Tells the player if they are hot or cold
    */
    public void printHotOrCold(int guess) {

        int offBy = guess - num;

        if (offBy == 1 || offBy == -1) {// if they are over or under by 1
            System.out.println("Hot");
        } else if (guess != num) {// if they are further than 1 away
             System.out.println("Cold");
        }

        tries++;

    }

    /**
    * Returns the number of wins and makes a new header
    * 
    * @return the String with the number of wins and new header
    */
    public String wins() {
        String record = String.format("You have won %d out of %d rounds. \n\n",wins,rounds);
        return record;
    }

    /**
    * Returns the number of rounds played
    * 
    * @return rounds the number of rounds
    */
    public int getRounds() {
        return rounds;
    }

}