如何将数据从线程发送到主活动java android
我有一个线程,我想做一些计算,然后发送到我的程序的主要活动。我怎么能做到 线是如何将数据从线程发送到主活动java android,java,android,multithreading,Java,Android,Multithreading,我有一个线程,我想做一些计算,然后发送到我的程序的主要活动。我怎么能做到 线是 class RemindTask extends TimerTask { public void run() { flag = true; System.out.println(" Hello World!"); for (int e=0; e<2; e++){ fileToReceive = fileparts.peek();
class RemindTask extends TimerTask {
public void run() {
flag = true;
System.out.println(" Hello World!");
for (int e=0; e<2; e++){
fileToReceive = fileparts.peek();
System.out.println("fileToReceive "+fileToReceive);
fileToReceive = fileparts.remove();
}
IntegerResult = 4;
flag=false;
}
然后我需要把IntegerResult带到主活动
大体上如此
主要方法是
int i=0;
//IntegerResult = 4; here i need to take the result of the thread
while (!fileparts.isEmpty() ) { //&& !fileparts1.isEmpty() && (flag == false)
String[] myStringArray = new String[IntegerResult];
for (int e=0; e<IntegerResult; e++){
if (fileToReceive != null && !fileparts.isEmpty() ){
fileToReceive = fileparts.peek();
myStringArray[e] = fileToReceive;
fileToReceive = fileparts.remove();
} else {
myStringArray[e] = " ";
}
System.out.println("myStringArray["+e+"] " + myStringArray[e]);
}
inti=0;
//积分结果=4;这里我需要获取线程的结果
而(!fileparts.isEmpty()){/&&!fileparts1.isEmpty()&&(flag==false)
字符串[]myStringArray=新字符串[IntegerResult];
对于(int e=0;e更新
使用自定义BroadcastReceiver
在ActivityA.java中写下这个
Intent intent = new Intent();
intent.putExtra("message","hi");
intent.setAction("com.android.activity.SEND_DATA");
sendBroadcast(intent);
private BroadcastReceiver mMessageReceiver = new BroadcastReceiver() {
@Override
public void onReceive(Context context, Intent intent) {
// Extract data included in the Intent
String message = intent.getStringExtra("message");
Log.d("receiver", "Got message: " + message);
}
};
在ServiceA.java/ActivityB.java中编写
Intent intent = new Intent();
intent.putExtra("message","hi");
intent.setAction("com.android.activity.SEND_DATA");
sendBroadcast(intent);
private BroadcastReceiver mMessageReceiver = new BroadcastReceiver() {
@Override
public void onReceive(Context context, Intent intent) {
// Extract data included in the Intent
String message = intent.getStringExtra("message");
Log.d("receiver", "Got message: " + message);
}
};
现在注册Receiver
LocalBroadcastManager.getInstance(mContext).registerReceiver(mMessageReceiver,
new IntentFilter("com.android.activity.SEND_DATA"));
看来你需要的是
您可以按照Rstar的建议使用服务,但这可能有点过头了。有两种方法:
如前所述,在异步任务上使用此选项
创建一个处理程序来接收响应
比如:
public static int YOUR_INT_MESSAGE = 100;
class RemindTask extends TimerTask {
public void run() {
flag = true;
System.out.println(" Hello World!");
for (int e=0; e<2; e++){
fileToReceive = fileparts.peek();
System.out.println("fileToReceive "+fileToReceive);
fileToReceive = fileparts.remove();
}
IntegerResult = 4;
flag=false;
Message msg = new Message();
msg.what = YOUR_INT_MESSAGE;
msg.obj = IntegerResult;
YourActivity.this.handler.sendMessage(msg);
}
public static int YOUR_int_MESSAGE=100;
类任务扩展TimerTask{
公开募捐{
flag=true;
System.out.println(“你好,世界!”);
对于(int e=0;这是一个常见问题解答。您应该考虑使用阻止队列
,例如LinkedBlockingQueue
。它允许多个线程共享信息,并为您处理所有同步和信令。如果您的答案中只包含一个链接,则应将其作为注释发布。