Java 从Servlet输出模板的最佳方法

Java 从Servlet输出模板的最佳方法,java,servlets,google-closure-templates,Java,Servlets,Google Closure Templates,从闭包模板渲染或输出大豆模板到浏览器的最佳方法是什么 目前我有以下几点: 包de.envisia.erp.web.servlet import java.io.File; import java.io.IOException; import javax.servlet.ServletContext; import javax.servlet.ServletException; import javax.servlet.annotation.WebServlet; import javax.se

从闭包模板渲染或输出大豆模板到浏览器的最佳方法是什么

目前我有以下几点: 包de.envisia.erp.web.servlet

import java.io.File;
import java.io.IOException;

import javax.servlet.ServletContext;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import com.google.template.soy.SoyFileSet;

import com.google.template.soy.tofu.SoyTofu;
/**
 * Servlet implementation class EntryPoint
 */
@WebServlet("/EntryPoint")
public class EntryPoint extends HttpServlet {
    private static final long serialVersionUID = 1L;

    /**
 * @see HttpServlet#HttpServlet()
 */
public EntryPoint() {
    super();
    // TODO Auto-generated constructor stub
}

/**
 * @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
 */
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    ServletContext servletContext = this.getServletContext();
    String pathContext = servletContext.getRealPath("/WEB-INF/");
    //response.getWriter().println(pathContext);

    SoyFileSet sfs = new SoyFileSet.Builder().add(new File(pathContext + "\\templates\\hello.soy")).build();
    SoyTofu tofu = sfs.compileToTofu();
    String out = tofu.newRenderer("hello.world").render();
    response.getWriter().println(out);
}

/**
 * @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
 */
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    // TODO Auto-generated method stub
    }

}
但是我认为使用响应对象的println甚至print()方法不是一个好的做法,有没有更好的方法?

看看

基本思想是创建一个特殊的servlet并向其转发请求:

RequestDispatcher rd = getServletContext().getRequestDispatcher("/soy/products.boat.sailingBoatView");
rd.forward(req, resp);

为什么不使用write方法呢。但是,代码中的弱点在于,您正在对每个请求编译模板,这将非常缓慢。