Java 活动在运行服务时冻结

我有一个按钮，按下后，启动服务。此服务开始从设备记录信息。但是，当我按下跑步按钮时，屏幕会暂时冻结约8秒，同时记录，然后一旦完成，屏幕就会解冻，会显示一条祝酒信息（这意味着只要你按下按钮就会显示），然后我可以做任何事情。如果我再次进入应用程序屏幕，当应用程序正在记录日志时（注意：服务总是在运行，因此不会冻结它，只是记录日志），那么活动将再次冻结，并且在日志记录完成之前，不允许我做任何事

我尝试过异步任务，并在一个新的可运行/新线程上运行，但这些似乎都不适合我。我不确定是否正确地实现了它们，但我想解决这个问题

以下是服务类中的onstart命令：

    @Override
public int onStartCommand(Intent intent, int flags, int startId) {
    // THIS WOULD BE THE METHOD THAT RUNS WHATEVER YOU WANT TO DO EVERY SO OFTEN SO FOR ME THIS IS GETTING ALL DATA ETC
    getProcessInfo();

    //  LOG DELAY = SECONDS BETWEEN RUNNING SERVICE/METHOD. SET AT THE TOP
    myPendingIntent = PendingIntent.getService(this, 0, intent, PendingIntent.FLAG_UPDATE_CURRENT);
    Alarmmgr.set(AlarmManager.RTC_WAKEUP, System.currentTimeMillis()+LOG_DELAY*1000, myPendingIntent);
    Intent notificationIntent = new Intent(this, LogOrCheck.class);
    PendingIntent contentIntent = PendingIntent.getActivity(this,
            101, notificationIntent,
            PendingIntent.FLAG_NO_CREATE);

    NotificationManager nm = (NotificationManager) this
            .getSystemService(Context.NOTIFICATION_SERVICE);

    Resources res = this.getResources();
    Notification.Builder builder = new Notification.Builder(this);

    builder.setContentIntent(contentIntent)
                .setSmallIcon(R.drawable.arrow_up_float)
                .setLargeIcon(BitmapFactory.decodeResource(getResources(), R.drawable.arrow_down_float))
                .setWhen(System.currentTimeMillis())
                .setAutoCancel(true)
                .setContentTitle("Androigenius")
                .setContentText("Service running OK");
    Notification n = builder.getNotification();


    startForeground(100, n);
    return Service.START_STICKY;
}

这就是我称之为startService的地方：

but1.setOnClickListener(new View.OnClickListener() {
        public void onClick(View v) {

            if (isClicked) {
                Context context = getApplicationContext();
                Toast toast = Toast.makeText(context, "Please press 'MINIMIZE' at the top to continue logging.", Toast.LENGTH_LONG);
                toast.setGravity(Gravity.TOP|Gravity.RIGHT, 10, 55);
                toast.show();
                System.out.println("Start logging");
                but1.setText("Stop Logging");
                but1.setTextColor(Color.RED);
                // START SERVICE, DONE. (STOP IS BELOW).
                startService(myIntent);
                isClicked = false;
            } 
            else if (!isClicked) {
                System.out.println("Stop Logging");
                but1.setText("Start Logging");
                // STOP SERVICE, DONE.
                stopService(myIntent);
                but1.setTextColor(getResources().getColor(color.cornblue));
                isClicked = true;
            }

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默认情况下，服务也在应用程序的主线程中运行，用户界面操作在主线程中进行。因此，如果在onStartCommand（）方法中执行长任务，它将阻塞主线程

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为了避免这个问题，您必须将日志记录任务迁移到一个单独的线程中。您可以使用AsycTask类来执行此操作。有关如何使用该类，请参阅。

服务在导致“冻结”的UI线程上运行。使用IntentService将创建一个在后台自动运行的服务，而不是在UI线程上运行。以下是IntentService类的一些详细信息：

    @Override
public int onStartCommand(Intent intent, int flags, int startId) {
    // THIS WOULD BE THE METHOD THAT RUNS WHATEVER YOU WANT TO DO EVERY SO OFTEN SO FOR ME THIS IS GETTING ALL DATA ETC
    getProcessInfo();

    //  LOG DELAY = SECONDS BETWEEN RUNNING SERVICE/METHOD. SET AT THE TOP
    myPendingIntent = PendingIntent.getService(this, 0, intent, PendingIntent.FLAG_UPDATE_CURRENT);
    Alarmmgr.set(AlarmManager.RTC_WAKEUP, System.currentTimeMillis()+LOG_DELAY*1000, myPendingIntent);
    Intent notificationIntent = new Intent(this, LogOrCheck.class);
    PendingIntent contentIntent = PendingIntent.getActivity(this,
            101, notificationIntent,
            PendingIntent.FLAG_NO_CREATE);

    NotificationManager nm = (NotificationManager) this
            .getSystemService(Context.NOTIFICATION_SERVICE);

    Resources res = this.getResources();
    Notification.Builder builder = new Notification.Builder(this);

    builder.setContentIntent(contentIntent)
                .setSmallIcon(R.drawable.arrow_up_float)
                .setLargeIcon(BitmapFactory.decodeResource(getResources(), R.drawable.arrow_down_float))
                .setWhen(System.currentTimeMillis())
                .setAutoCancel(true)
                .setContentTitle("Androigenius")
                .setContentText("Service running OK");
    Notification n = builder.getNotification();


    startForeground(100, n);
    return Service.START_STICKY;
}

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我也有同样的问题。。嗯，我知道Intent服务是在一个单独的线程上运行的，但我的UI仍然冻结。我在intent服务上做了一个很长的db操作，我不明白为什么它会冻结，因为它运行在一个完全不同的线程上。