Java 在jmockit中,如何模拟void方法在第一次调用时抛出异常而不在后续调用中抛出异常?

Java 在jmockit中,如何模拟void方法在第一次调用时抛出异常而不在后续调用中抛出异常?,java,jmockit,Java,Jmockit,我可以使void方法抛出如下异常: class TestClass { public void send(int a) {}; } @Mocked private TestClass mock; @Test public void test() throws Exception { new Expectations() { { mock.send(var1); this.result = new Exceptio

我可以使void方法抛出如下异常:

class TestClass {
    public void send(int a) {};
}

@Mocked
private TestClass mock;

@Test
public void test() throws Exception {
    new Expectations() {
        {
            mock.send(var1);
            this.result = new Exception("some exception");
        }
    };
}
但是,如果我希望void方法在第一次调用时抛出异常,而不是在后续调用时抛出异常,那么这些方法似乎不起作用:

@Test
public void test() throws Exception {
    new Expectations() {
        {
            mock.send(var1);
            this.result = new Exception("some exception");
            this.result = null;
        }
    };
}

它们都不会引发异常


使用JMockit可以实现这一点吗?从文档和文档中我不清楚。

以下测试对我来说很好:

static class TestClass { void send(int a) {} }
@Mocked TestClass mock;
int var1 = 1;

@Test
public void test() {
    new Expectations() {{
        mock.send(var1);
        result = new Exception("some exception");
        result = null;
    }};

    try { mock.send(var1); fail(); } catch (Exception ignore) {}
    mock.send(var1);
}
static class TestClass { void send(int a) {} }
@Mocked TestClass mock;
int var1 = 1;

@Test
public void test() {
    new Expectations() {{
        mock.send(var1);
        result = new Exception("some exception");
        result = null;
    }};

    try { mock.send(var1); fail(); } catch (Exception ignore) {}
    mock.send(var1);
}