Java 无法使用Json解析我的列表的符号
下面我试图创建一个列表,但是符号“Feed”无法解析。我遗漏了哪些应该包括在内。这个想法是从我创建的文件中获取新闻文章Java 无法使用Json解析我的列表的符号,java,list,android-studio,resolve,Java,List,Android Studio,Resolve,下面我试图创建一个列表,但是符号“Feed”无法解析。我遗漏了哪些应该包括在内。这个想法是从我创建的文件中获取新闻文章 public class Utils { private static final String TAG = "Utils"; public static List<Feed> loadFeeds(Context context){ try{ GsonBuilder builder = new GsonBuil
public class Utils {
private static final String TAG = "Utils";
public static List<Feed> loadFeeds(Context context){
try{
GsonBuilder builder = new GsonBuilder();
Gson gson = builder.create();
JSONArray array = new JSONArray(loadJSONFromAsset(context, "news.json"));
List<Feed> feedList = new ArrayList<>();
for(int i=0;i<array.length();i++){
Feed feed = gson.fromJson(array.getString(i), Feed.class);
feedList.add(feed);
}
return feedList;
}catch (Exception e){
Log.d(TAG,"seedGames parseException " + e);
e.printStackTrace();
return null;
}
}
private static String loadJSONFromAsset(Context context, String jsonFileName) {
String json = null;
InputStream is = null;
try {
AssetManager manager = context.getAssets();
Log.d(TAG,"path "+jsonFileName);
is = manager.open(jsonFileName);
int size = is.available();
byte[] buffer = new byte[size];
is.read(buffer);
is.close();
json = new String(buffer, "UTF-8");
} catch (IOException ex) {
ex.printStackTrace();
return null;
}
return json;
}
}
公共类Utils{
私有静态最终字符串TAG=“Utils”;
公共静态列表加载源(上下文){
试一试{
GsonBuilder=新的GsonBuilder();
Gson Gson=builder.create();
JSONArray数组=新的JSONArray(loadJSONFromAsset(context,“news.json”);
List feedList=新的ArrayList();
对于(int i=0;i要创建列表
,您必须创建类提要
,并将其导入到您的Utils
类中