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Java 解析:无法上载文件_Java_Android_File Upload_Parse Platform - Fatal编程技术网

Java 解析:无法上载文件

Java 解析:无法上载文件,java,android,file-upload,parse-platform,Java,Android,File Upload,Parse Platform,我想做一个有上传文件功能的应用。但问题是,我找不到哪里做错了 首先,选择文件 public void onClick(View arg0) { Intent intent = new Intent(Intent.ACTION_GET_CONTENT); intent.setType("*/*"); // intent.addCategory(Intent.CATEGORY_OPENABLE); t

我想做一个有上传文件功能的应用。但问题是,我找不到哪里做错了

首先,选择文件

public void onClick(View arg0) {

            Intent intent = new Intent(Intent.ACTION_GET_CONTENT);
            intent.setType("*/*");
            // intent.addCategory(Intent.CATEGORY_OPENABLE);

            try {
                Log.d(TAG, "Select file");
                startActivityForResult(
                        Intent.createChooser(intent, "Select a File to Upload"),
                        RESULT_LOAD_FILE);
            } catch (android.content.ActivityNotFoundException ex) {
                // Potentially direct the user to the Market with a Dialog
                Toast.makeText(MainActivity.this, "Please install a File Manager.", Toast.LENGTH_SHORT).show();
            }

            // here
        }
我想在基于logcat选择文件时没有问题。但是

public void onActivityResult(int requestCode, int resultCode, Intent data)
{
    super.onActivityResult(requestCode, resultCode, data);
    Log.d(TAG, requestCode+"/"+RESULT_LOAD_FILE+"/"+resultCode+"/"+RESULT_OK);

    if (data != null) Log.d(TAG, data.toString());
    else Log.d(TAG, "data null");

    // get file name
    String fileNameSegments[] = filePath.split("/");
    fileName = fileNameSegments[fileNameSegments.length - 1];

    // convert it to byte
    byte[] fileByte = fileName.getBytes();

    // Create the ParseFile
    ParseFile file = new ParseFile(fileName, fileByte);

    // Upload the image into Parse Cloud
    file.saveInBackground();

    // Create a New Class called "ImageUpload" in Parse
    ParseObject fileupload = new ParseObject("FileUpload");

    // Create a column named "ImageName" and set the string
    fileupload.put("FileName", fileName);

    // Create a column named "ImageFile" and insert the image
    fileupload.put("DocFile", file);

    // Create the class and the columns
    fileupload.saveInBackground();

    // Show a simple toast message
    Toast.makeText(MainActivity.this, "File Uploaded", Toast.LENGTH_SHORT).show();
}
日志猫分别显示
requestCode
RESULT\u LOAD\u FILE
resultCode
RESULT\u OK
1、1、-1和-1。并且数据不为null,如logcat:
Intent{dat中所示=content://com.android.externalstorage.documents/document/0A09-1112:Download/Contact n.pdf flg=0x1}

在我点击.pdf文件后,它触发了toast
出现了一些问题,但我找不到原因


编辑: 将文件路径转换为字节后抛出空指针异常,当我删除try-catch块时,应该是这样的

 Uri uri = data.getData();
            // get path
            filePath = uri.getPath();

            // get file name
            String fileNameSegments[] = filePath.split("/");
            fileName = fileNameSegments[fileNameSegments.length - 1];

            // convert it to byte
            byte[] fileByte = fileName.getBytes();

            // Create the ParseFile
            ParseFile file = new ParseFile(fileName, fileByte);

            // Upload the file into Parse Cloud
            file.saveInBackground();

            // Create a New Class called "FileUpload" in Parse
            ParseObject fileUpload = new ParseObject("FileUpload");

            // Create a column named "FileName" and set the string
            fileUpload.put("FileName", fileName);

            Log.d(TAG, "image file");
            // Create a column named "ImageFile" and insert the image
            fileUpload.put("DocFile", file);

            // Create the class and the columns
            fileUpload.saveInBackground();

            Log.d(TAG, "toast");
            // Show a simple toast message
            Toast.makeText(MainActivity.this, "File Uploaded",
                    Toast.LENGTH_SHORT).show();

虽然类不是在parse dashboard中创建的,但我想这需要另一篇文章。

引发异常的消息是什么???@MoNazemi
未能将结果ResultInfo{who=null,request=1,result=-1,data=Intent{dat=content:..}传递到活动{com.example…….MainActivity}:java.lang.NullPointerException:尝试在空对象引用上调用虚拟方法“java.lang.String[]java.lang.String.split(java.lang.String)”
它说变量
filePath
为空,在哪里初始化??@MoNazemi
String selectedFile=data.getData().getPath()啊!?为什么要这样做
stringfilenamesegments[]=filePath.split(“/”)然后呢?