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java服务器与php客户端的SocketServer通信_Java_Php_Sockets_Serversocket - Fatal编程技术网

java服务器与php客户端的SocketServer通信

java服务器与php客户端的SocketServer通信,java,php,sockets,serversocket,Java,Php,Sockets,Serversocket,我试图在Java中的SocketServer服务器和php中的Socket客户端之间建立通信。 客户端能够连接到主机,客户端能够发送消息,服务器能够成功读取消息。但是,当SocketServer向客户端写入时,客户端不会从服务器接收消息 我已经阅读了关于同一场景java php套接字通信的其他问题,但我似乎无法找到导致问题的原因 如果我使用Java套接字作为客户端,那么通信在两种方式下都能完美地工作 服务器: 客户: 有人能告诉我这里有什么问题吗 在服务器端,代码需要一个以linefeed结尾的

我试图在Java中的SocketServer服务器和php中的Socket客户端之间建立通信。 客户端能够连接到主机,客户端能够发送消息,服务器能够成功读取消息。但是,当SocketServer向客户端写入时,客户端不会从服务器接收消息

我已经阅读了关于同一场景java php套接字通信的其他问题,但我似乎无法找到导致问题的原因

如果我使用Java套接字作为客户端,那么通信在两种方式下都能完美地工作

服务器:

客户:


有人能告诉我这里有什么问题吗

在服务器端,代码需要一个以linefeed结尾的行,使用您发送的php

socket_write($socket, $message, strlen($message)); 

请检查相应发送的数据,确保发送换行符。

谢谢Ozgen,这就是问题所在!服务器正在寻找终点线!
class Client {

    private $address;
    private $port;

    public function __construct($address, $port){
        $this->address = $address;
        $this->port = $port;
        $this->init();
    }

    private function init(){

        //create socket
        if(! $socket = socket_create(AF_INET, SOCK_STREAM, getprotobyname('tcp'))){
            $this->showError("socket create");
        };

        //establish connection
        socket_connect($socket, $this->address, $this->port);

        //write to server
        $message = "I am a client";
        socket_write($socket, $message, strlen($message)); //Send data

        echo "Listening to Server\n";

        //read from server
        if(!$reponse = socket_read($socket, 2048, PHP_NORMAL_READ)){
            $this->showError("socket read");
        }

        //print response
        echo "Response from server------------------\n";
        echo $reponse;

        socket_close($socket);

    }

    private function showError($message){
        echo ("Error: ".$message);
        exit(666);

    }

}

$address="localhost";$port=9005;
echo "Testing Client Server\n";
$client = new Client($address, $port);
socket_write($socket, $message, strlen($message));