Java 集合的二进制搜索不起作用

我不熟悉JAVA和Netbeans，这是我必须做的： 用户可以在输入框中输入标题CD，然后按删除按钮将CD从列表中删除。如果收藏中不存在CD，则发件箱中会显示一条消息，说明此情况。 这就是我所做的：

ArrayList <String> songs = new ArrayList();
Collections.addAll(songs, "Metric - Fantasies", "\nBeatles - Abbey Road", "\nPearl Jam - Ten", "\nDoors - Alive", "\nThe Rolling Stones - Gimme Shelter\n");
int remove = Collections.binarySearch(songs, artistinput.getText());
    if (remove < 0)
    {
        output.setText("That CD does not exist in the collection, please try again");
    }
    else if (remove >= 0)
    {
        boolean delete=songs.remove(artistinput.getText());{
    output.setText("Original Songs \n" +delete);

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这是我唯一没有弄明白的部分。这不起作用，因为它只显示输出。SetText如果集合中不存在CD，请重试；每次我键入歌曲并按“删除”。感谢您的帮助，并提前向您表示感谢

使用java 8，您可以尝试以下方法：

    List<String> songs = new ArrayList<String>();
    int size = songs.size();
    Collections.addAll(songs, "Metric - Fantasies", "\nBeatles - Abbey Road", "\nPearl Jam - Ten", "\nDoors - Alive", "\nThe Rolling Stones - Gimme Shelter\n");
    songs.removeIf(o->o.equalsIgnoreCase(artistinput.getText()));
    int arSize = songs.size();
    if(size != arSize){
        System.out.println("Original Songs \\n" + (size-arSize));
    }else System.out.println("That CD does not exist in the collection, please try again");

为了使用binarysearch，您必须确保数组是有序的。你没有对你的歌曲进行分类，所以你没有得到预期的结果。我不知道您为什么要为歌曲名添加\n

另一种解决方案是先对数组排序。详情如下:

    ArrayList <String> songs = new ArrayList();
    Collections.addAll(songs, "Metric - Fantasies", "\nBeatles - Abbey Road", "\nPearl Jam - Ten", "\nDoors - Alive", "\nThe Rolling Stones - Gimme Shelter\n");
    Collections.sort(songs);//////sort the songs
   int remove = Collections.binarySearch(songs, artistinput.getText());
   if (remove < 0)
   {
        output.setText("That CD does not exist in the collection, please try again");
   }
  else if (remove >= 0)
  {
       boolean delete=songs.remove(artistinput.getText());{
       output.setText("Original Songs \n" +delete);
  }

---

简单快捷的方法。我改变了你的输入和输出系统，但我猜这对你的班级来说是好的

import java.util.ArrayList;
import java.util.Collections;
import java.util.Scanner;

public class dumbshit{

public static void main(String args[]){

Scanner scan = new Scanner(System.in);

ArrayList<String> songs = new ArrayList<String>();
songs.add("Metric - Fantasies");
songs.add("Beatles - Abbey Road");
songs.add("Pearl Jam - Ten");
//etc
//this can obviously be done better
Collections.sort(songs);
int index = Collections.binarySearch(songs, scan.nextLine());
    if (index < 0)
    {
        System.out.println("That CD does not exist in the collection, please try again");
    }
    else if (index >= 0)
    {
        songs.remove(index);
        for(int i = 0; i < songs.size(); i++){
            System.out.println( songs.get(i) );
        }
    }
 }
}

---

您的歌曲未排序。并且它包含换行符\n，为什么？还有，是吗？医生，您不太可能从您的输入中\n获得文本。这不是我，即使我们的问题有点相同，所以它显示在新行上，因为我使用的是textfield，而不会显示在新行上。所以，这就是我的老师建议我做的