递归比较两个json节点并在java中打印不同的值
我想比较java中的两个大json节点,如果它们不同,我需要打印两个节点中不同的值。 如果节点不相等,但不告诉特定的不同值,则JsonNode.equals()返回false 谢谢 代码示例:递归比较两个json节点并在java中打印不同的值,java,json,Java,Json,我想比较java中的两个大json节点,如果它们不同,我需要打印两个节点中不同的值。 如果节点不相等,但不告诉特定的不同值,则JsonNode.equals()返回false 谢谢 代码示例: import org.codehaus.jackson.JsonNode; import org.codehaus.jackson.map.ObjectMapper; import org.codehaus.jackson.map.util.JSONPObject; im
import org.codehaus.jackson.JsonNode;
import org.codehaus.jackson.map.ObjectMapper;
import org.codehaus.jackson.map.util.JSONPObject;
import org.json.JSONException;
import org.json.JSONObject;
import java.io.IOException;
import java.util.Iterator;
import java.util.Map;
public class TestJsonComp
{
static String json = "{\n" +
" \"d\" :\n" +
" {\n" +
" \"results\" :\n" +
" [\n" +
" {\n" +
" \"__metadata\" :\n" +
" {\n" +
" \"id\" : \" ##ServiceRoot##/Submit('##RequisitionUniqueName##')\",\n" +
" \"uri\" : \"##ServiceRoot##/Submit('##RequisitionUniqueName##')\",\n" +
" \"type\" : \".submitResponse\",\n" +
" \"etag\" : \"W/\\\"##RequisitionUniqueName##\\\"\"\n" +
" },\n" +
" \"status\" : \"ERROR\",\n" +
" \"uniqueName\" : \"##RequisitionUniqueName##\",\n" +
" \"errors\" :\n" +
" {\n" +
" \"results\" :\n" +
" [\n" +
" {\n" +
" \"__metadata\" :\n" +
" {\n" +
" \"id\" : \"##ServiceRoot##/RequisitionErrors(0)\",\n" +
" \"uri\" : \"##ServiceRoot##/RequisitionErrors(0)\",\n" +
" \"type\" : \".errors\",\n" +
" \"etag\" : \"W/\\\"0\\\"\"\n" +
" },\n" +
" \"id\" : 0,\n" +
" \"error_description\" : \"title.\"\n" +
" },\n" +
" {\n" +
" \"__metadata\" :\n" +
" {\n" +
" \"id\" : \"##ServiceRoot##/RequisitionErrors(1)\",\n" +
" \"uri\" : \"##ServiceRoot##/RequisitionErrors(1)\",\n" +
" \"type\" : \".errors\",\n" +
" \"etag\" : \"W/\\\"1\\\"\"\n" +
" },\n" +
" \"id\" : 1,\n" +
" \"error_description\" : \"Line item 1 must be set.\"\n" +
" }\n" +
" ]\n" +
" }\n" +
" }\n" +
" ]\n" +
" }\n" +
"}";
static String jsonCompare = "{\n" +
" \"d\" :\n" +
" {\n" +
" \"results\" :\n" +
" [\n" +
" {\n" +
" \"__metadata\" :\n" +
" {\n" +
" \"id\" : \"##ServiceRoot##/Submit('##RequisitionUniqueName##')\",\n" +
" \"uri\" : \"##ServiceRoot##/Submit('##RequisitionUniqueName##')\",\n" +
" \"type\" : \".submitResponse\",\n" +
" \"etag\" : \"W/\\\"##RequisitionUniqueName##\\\"\"\n" +
" },\n" +
" \"status\" : \"ERROR\",\n" +
" \"uniqueName\" : \"##RequisitionUniqueName##\",\n" +
" \"errors\" :\n" +
" {\n" +
" \"results\" :\n" +
" [\n" +
" {\n" +
" \"__metadata\" :\n" +
" {\n" +
" \"id\" : \"##ServiceRoot##/RequisitionErrors(0)\",\n" +
" \"uri\" : \"##ServiceRoot##/RequisitionErrors(0)\",\n" +
" \"type\" : \".errors\",\n" +
" \"etag\" : \"W/\\\"0\\\"\"\n" +
" },\n" +
" \"id\" : 0,\n" +
" \"error_description\" : \"title.\"\n" +
" },\n" +
" {\n" +
" \"__metadata\" :\n" +
" {\n" +
" \"id\" : \"##ServiceRoot##/RequisitionErrors(1)\",\n" +
" \"uri\" : \"##ServiceRoot##/RequisitionErrors(1)\",\n" +
" \"type\" : \".errors\",\n" +
" \"etag\" : \"W/\\\"1\\\"\"\n" +
" },\n" +
" \"id\" : 1,\n" +
" \"error_descriptio\" : \"Line item 1 must be set.\"\n" +
" }\n" +
" ]\n" +
" }\n" +
" }\n" +
" ]\n" +
" }\n" +
"}";
public static void main (String args []) throws IOException, JSONException
{
ObjectMapper objectMapper = new ObjectMapper();
JsonNode n1 = objectMapper.readTree(json);
JsonNode n2 = objectMapper.readTree(jsonCompare);
System.out.print(n1.equals(n2));
}
}
检查
您可以获得一个节点的子节点列表。然后在子节点上循环,获取键/值,并使用键比较第二个节点的每个元素。检查
您可以获得一个节点的子节点列表。然后在子节点上循环,获取键/值并使用键比较第二个节点的每个元素。我建议使用文件比较器并逐行比较。如果您还注意节点中元素的顺序,这将起作用。如果未考虑顺序,则首先使用JsonNode.equals()检查相等性,并且仅当节点不相等时,才使用文件比较器打印差异 我建议使用文件比较器,逐行比较。如果您还注意节点中元素的顺序,这将起作用。如果未考虑顺序,则首先使用JsonNode.equals()检查相等性,并且仅当节点不相等时,才使用文件比较器打印差异 向我们展示您的代码和尝试以及json结构向我们展示您的代码和尝试以及json结构