Java 我们需要的是；前五名；id'；s"；从这个查询

我有人帮我，而且已经接近了，我需要从这个查询中获得前五个“id”。现在的情况是，我只拿到了一张身份证，而不是前五名。有人知道怎么纠正吗？以下是查询：

(
SELECT id,
     firstName,
     lastName,
     SUM(fileSize) AS TotalBytes,
     SUM(fileSize)/COUNT(*) AS Average
FROM   roster_cs368 AS a
JOIN htmp_cs368  AS b USING (id)
) UNION (
SELECT id,
     firstName,
     lastName,
     SUM(fileSize) AS TotalBytes,
     SUM(fileSize)/COUNT(*) AS Average
FROM   roster_cs368 AS a
JOIN atmp_cs368  AS b USING (id)
)
ORDER BY TotalBytes DESC
LIMIT 5

谢谢大家!！这也是更大程序的一部分，因此是java标记

以下是模式：

mysql> select * from roster_cs368
-> ;
+--------+-----------+-----------+
| id     | firstName | lastName  |
+--------+-----------+-----------+
| apn7cf | Allen     | Newton    |
| atggg3 | andrew    | goebel    |

主键在哪里

mysql> select * from htmp_cs368;
+------------+----------+------------+----------+----------+-------+------+-------+----------------------+
| filePerms  | numLinks | id         | idGroup  | fileSize | month | day  | time  | fileName             |
+------------+----------+------------+----------+----------+-------+------+-------+----------------------+
| drwx------ |        2 | schulte    | faculty  |      289 | Nov   |    7 | 2011  | Java                 |
| -rw-r--r-- |        1 | schulte    | faculty  |      136 | Apr   |   29 | 2012  | LD                   |
| drwxr-xr-x |        3 | schulte    | faculty  |      177 | Mar   |   20 | 2012  | Upgrade              |

这里没有主键

mysql> select * from atmp_cs368;
+------------+----------+--------------+----------+----------+-------+------+-------+-----------------------------+
| filePerms  | numLinks | id           | idGroup  | fileSize | month | day  | time  | fileName                    |
+------------+----------+--------------+----------+----------+-------+------+-------+-----------------------------+
| drwxr-xr-x |        2 | remierm      | 203      |      245 | Sep   |   17 | 14:40 | 148360_sun_studio_12        |
| drwx---rwx |       31 | antognolij   | sasl     |     2315 | Oct   |   24 | 12:28 | 275                         |
| -rwx------ |        1 | kyzvdb       | student  |       36 | Sep   |   19 | 13:05 | 275hh                       |

这里没有主键

我的问题是：

produce a list of the five members of roster_cs368,
    and their ids who use the most space (number of bytes)
    in htmp_cs368 and atmp_cs368 in descending order--
    greediest first.  display total number of bytes and
    average size of file

---

您可以这样做：

SELECT * FROM(
(
SELECT id,
     firstName,
     lastName,
     SUM(fileSize) AS TotalBytes,
     SUM(fileSize)/COUNT(*) AS Average
FROM   roster_cs368 AS a
JOIN htmp_cs368  AS b USING (id)
) UNION (
SELECT id,
     firstName,
     lastName,
     SUM(fileSize) AS TotalBytes,
     SUM(fileSize)/COUNT(*) AS Average
FROM   roster_cs368 AS a
JOIN atmp_cs368  AS b USING (id)
)
) as somealias ORDER BY TotalBytes DESC
LIMIT 5

---

定义前5名。。。也许和我们分享这个模式，给我们一个预期输出的例子，实际输出是什么，等等on@Tim添加了模式和查询。我感谢您的帮助，但它给了我一个错误

您的SQL语法有错误；查看与您的MySQL服务器版本对应的手册，以了解使用near'FROM（（选择id、firstName、lastName、SUM（fileSize））的正确语法作为第1行的TotalByt，它有一个错误，我已经用一个固定版本更新了我的答案，请尝试。仍然只有1个用户，然后为空。我已经更新了我的原始帖子以包含架构。